Class 6 Mathematics Chapter 3: Number Play

Number Play is Chapter 3 of NCERT / CBSE Class 6 Mathematics. This page has the complete chapter notes across 4 topics , 80 practice MCQs with answers and explanations , 36 important short and long questions and 60 flashcards — all written to the NCERT / CBSE syllabus and free to read.

What Numbers Can Tell Us

Numbers can describe an arrangement, not only a quantity. Children in a row report their taller neighbours, boxes in a table compete with the boxes beside them, and a number line turns size into position.

What you will be able to do

  • I can work out what each child in a row would call out, once I know their heights.
  • I can explain why the two children at the ends of a row can never call out 2.
  • I can find the supercells in a row of boxes and say why the others miss out.
  • I can work out the worth of one step on a number line and label the blank marks.

Key points

  • A number can report an arrangement. Each child calls out how many of their neighbours are taller than they are.

  • A child at the end of a row has one neighbour only, so 2 is never an answer there.

  • The tallest child in a row always calls out 0, so a row of all ones cannot happen.

  • The shortest child always has a taller neighbour, so a row of all zeros cannot happen either.

  • A box is a supercell when its number beats every box touching it, however many that is.

  • Two supercells can never sit side by side, because neither number can beat the other.

  • Colouring every second box gives the most supercells a row can hold.

  • On a number line the worth of one step is fixed by the labels, and it can be any size at all.

Full explanation

Meera lines up her friends

Meera plays a game in the school ground. Five friends stand in a row, shoulder to shoulder. Each one looks left and right, then calls out a single number. Meera writes down what she hears: 1, 1, 0, 1, 1. Her cousin sees the list and cannot make head or tail of it. The list looks like nonsense. It is not. Those five numbers describe the whole row.

The rule they are using

Every child counts the neighbours who are taller than they are. A child with a taller person on one side only calls out 1. A child with taller people on both sides calls out 2. A child who is taller than everyone beside them calls out 0. So the number is not the height. It is a count of taller neighbours.

Why the two ends are different

A child in the middle has a neighbour on the left and a neighbour on the right. A child at the end of the row has only one neighbour. That single fact decides a lot. An end child can call 0 or 1 and nothing else. Calling 2 would mean two taller neighbours, and there is nobody there to be the second one.

The tallest child always says nothing but zero

Somebody in the row is taller than everybody else. Nobody beside that child is taller. So the tallest child always calls out 0. This works however the children shuffle themselves. It also means a row can never be all ones. Wherever the tallest child stands, a 0 has to appear in the list.

Can every child call zero?

Try it and you will fail. Calling 0 means being taller than both your neighbours. Now think about the shortest child in the row. Somebody standing beside that child is taller, because everybody is. So the shortest child has to call 1 or 2, never 0. A row of all zeros is impossible.

Neighbours can call the same number

Meera's list begins 1, 1. That surprises people. It is easy to arrange. Put a short child, then a medium child, then a tall child. The first child sees a taller neighbour and says 1. The second child sees one shorter and one taller, so says 1 as well. Two neighbours saying the same thing is perfectly ordinary.

Reading the list backwards

The real fun starts when you are given the numbers and asked about the row. A 2 in the list marks a dip: that child is shorter than both neighbours. A 0 marks a peak. Peaks and dips cannot sit side by side, because a child cannot be taller and shorter than the same neighbour. So the list carries the shape of the row.

A table of numbers that compete

Now leave the ground and open your notebook. Write seven numbers in a row of boxes: 412, 806, 375, 940, 268, 719, 153. Colour a box when its number beats every number touching it. A coloured box is called a supercell. Three of these seven qualify. Find them before reading on.

Checking each box in turn

806 sits between 412 and 375, and beats both, so it is a supercell. 940 sits between 375 and 268, and beats both. 719 sits between 268 and 153, and beats both. The other four all lose to a neighbour. So the supercells here are 806, 940 and 719.

The end boxes count their own way

A box at the end of a row touches only one other box. So it has to beat one number, not two. That makes it easier for an end box to win, not harder. In our row 412 still loses, because 806 sits next to it. Swap 412 for 999 and the end box would win.

Two supercells never touch

Suppose two boxes sit side by side and both are coloured. The left one must beat the right one. The right one must beat the left one. Two numbers cannot each be bigger than the other. So that can never happen, and the coloured boxes always have a gap between them.

So how many can a row hold?

Colour one box, skip one, colour the next, and so on. That is the most you can manage. A row of seven boxes holds at most four supercells. A row of eight also holds four. A row of nine holds five. Work it out by filling a row with big and small numbers turn by turn.

Numbers have places, not just sizes

A number line does the same job in a different way. It turns size into position. The further right a number sits, the bigger it is. Two numbers you cannot tell apart in a list are obvious on a line, because one of them stands further along than the other.

One step is worth whatever the line says

Read the labels before you read the marks. On one line each step may be worth 200, so the marks run 3000, 3200, 3400 and onwards. On another each step may be worth 2, so the marks run 45670, 45672, 45674. The picture looks the same. Only the labels tell you the difference.

Finding a mark nobody has labelled

Very often a line labels two marks and leaves the rest blank. Count the gaps between the two labels. Share the difference out equally among them. That gives the worth of one step, and from there every blank mark can be filled in, going left as easily as right.

Concepts and terms

Reporting number

A number that describes a position rather than a quantity. In the lining-up game the number a child calls out counts their taller neighbours. It tells you nothing about the child's own height on its own.

Neighbour

Whoever stands immediately beside you, or whichever box touches yours. A child in the middle of a row has two neighbours and a child at the end has one. Counting neighbours first saves most of the mistakes.

Supercell

A box whose number is greater than the number in every box touching it. An end box has to beat one neighbour and a middle box has to beat two, so the test is easier at the ends of a row.

Step on a number line

The amount by which each mark rises above the mark before it. The step may be 1, or 200, or anything else. Two lines can look identical and carry completely different numbers.

Watch out!

Myth or reality

Case Study

Scenario:

A class is given two figures for a town: a population of 48,000 and a bus fare of 15 rupees. Meena is asked which number carries more information. She says the bigger one. Their teacher asks what each number would tell a visitor. The population says how many people live there, and that shapes how many schools and buses the town needs. The fare says what one journey costs. The class decides that neither is more informative, because they answer different questions. Meena rewrites her answer. A number means nothing on its own, and what it is counting is as much a part of it as its size.

Analysis:

Meena ranked the numbers by size. What a number counts, and the question it answers, decide what it can tell you.

Activity:

Find two numbers about your town. Write what question each one answers and who would need it.

Line up and call out

Title:

Line up and call out

What You Notice:

Every list holds at least one zero, and the ends never say 2. In the boxes, no two coloured cells ever end up touching, and four is the most you can squeeze out of seven boxes.

Did you know

A single row of numbers can hide a picture. The numbers 0, 2, 0, 2, 0 describe a row that goes tall, short, tall, short, tall.

Computers sort huge lists by asking the same small question again and again: is this item bigger than the one beside it?

Mapmakers mark hilltops and valley floors in much the same way, by comparing a place with the land touching it.

Memory tricks

What a child at the end of a row can say — One neighbour, one chance — An end child compares with a single person. So the answer is 0 or 1. There is no second neighbour to make it 2.

Spotting supercells quickly — Beat both sides, or the one side you have — Count the boxes touching yours first. Then check your number against each of them. Nothing else matters.

Practice MCQs with answers (20)

Q1 Five children of different heights stand in a row and each calls out the number of taller neighbours. What is the very first thing you should check for a child? beginner
  • A How tall that child is in centimetres
  • B Whether the child is standing on the left of the row
  • C How many children are in the row altogether
  • D How many neighbours that child has
Show answer
Answer: How many neighbours that child has
Why:

An end child compares with one person and a middle child with two, so the count of neighbours comes first.

Q2 A child standing at the end of a row calls out a number. Which numbers are open to that child? beginner
  • A Only 0
  • B Only 1
  • C 0 or 1
  • D 0, 1 or 2
Show answer
Answer: 0 or 1
Why:

One neighbour means at most one taller neighbour can be counted.

Q3 Heights in centimetres along a row are 118, 126, 148, 140 and 132. What does the child of 148 cm call out? beginner
  • A 0
  • B 1
  • C 2
  • D It depends on the row length
Show answer
Answer: 0
Why:

Both neighbours, 126 and 140, are shorter, so no taller neighbour is counted.

Q4 Heights in centimetres along a row are 118, 126, 148, 140 and 132. What does the child of 126 cm call out? intermediate
  • A 2, because the row is uneven on both sides
  • B 0, because 118 cm is shorter than she is
  • C 1, because she stands next to the end of the row
  • D 1, because only the 148 cm neighbour is taller
Show answer
Answer: 1, because only the 148 cm neighbour is taller
Why:

Her neighbours are 118 and 148, and only one of those beats her.

Q5 A row of children produces the list 1, 1, 1, 1. What can you say about it? intermediate
  • A It is fine, and the tallest child is at an end
  • B It is fine, and two children must be the same height
  • C It is impossible, because the tallest child has to call 0
  • D It is impossible, because a list may not repeat a number
Show answer
Answer: It is impossible, because the tallest child has to call 0
Why:

Somebody in the row beats everybody, and that child has no taller neighbour.

Q6 A child calls out 2. This means the child is ____ both neighbours. beginner
  • A taller than
  • B standing between
  • C the same height as
  • D shorter than
Show answer
Answer: shorter than
Why:

Two taller neighbours is exactly what a 2 reports.

Q7 Which statement about the lining-up game is true? intermediate
  • A A row of all zeros can be arranged if only the children are careful enough
  • B The shortest child always calls out 0
  • C A child at an end of the row often calls out 2
  • D Two children standing next to each other can call out the same number
Show answer
Answer: Two children standing next to each other can call out the same number
Why:

Short, medium and tall in that order gives 1, 1 from the first two children.

Q8 Match each child with what they always call out: (i) the tallest child, (ii) a child shorter than both neighbours. intermediate
  • A (i) 0 and (ii) 2
  • B (i) 1 and (ii) 0
  • C (i) 2 and (ii) 1
  • D (i) 0 and (ii) 1
Show answer
Answer: (i) 0 and (ii) 2
Why:

The tallest child counts nobody, and a child below both neighbours counts two.

Q9 A box in a table is coloured when its number is greater than ____. beginner
  • A the number in every box that touches it
  • B every other number written in the table
  • C the number on its left only
  • D the average of the whole table
Show answer
Answer: the number in every box that touches it
Why:

Only the boxes actually touching it are compared.

Q10 Consider these statements about the neighbour-counting row. I. A child at the end of a row has one neighbour, so 2 is never their answer. II. A row in which every child calls out 1 is possible. III. The tallest child in a row always calls out 0. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are correct. II is not: the tallest child must say 0, so a row of all ones cannot happen.

Q11 In that same row, why is 375 not a supercell? beginner
  • A Because it is an odd number and odd numbers cannot win
  • B Because 806 and 940 are both bigger than it
  • C Because it sits at the end of the row and has one neighbour
  • D Because a row may hold only two coloured boxes
Show answer
Answer: Because 806 and 940 are both bigger than it
Why:

A box must beat every neighbour, and 375 beats neither of its own.

Q12 Which of these is true about the box holding the smallest number in a table? intermediate
  • A It is always a supercell, since it is easy to find
  • B It is a supercell whenever it sits at an end of the row
  • C It is never a supercell when the table has more than one box
  • D It becomes a supercell after the table is rearranged
Show answer
Answer: It is never a supercell when the table has more than one box
Why:

Every neighbour it has is bigger than it, so it loses each comparison.

Q13 Two boxes stand side by side. Can both be coloured as supercells? intermediate
  • A Yes, if both numbers are over a thousand
  • B Yes, if the two numbers are close together
  • C No, because each would have to beat the other
  • D No, because a table allows only three coloured boxes
Show answer
Answer: No, because each would have to beat the other
Why:

No pair of numbers is each greater than the other.

Q14 Assertion: A row in which every child calls out 0 cannot happen. Reason: The shortest child in the row always has a taller neighbour. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true, and the reason settles it. Whoever is shortest has to count at least one taller neighbour.

Q15 Sunita wants as many coloured boxes as possible in her row. Which plan works? advanced
  • A Write the numbers in order, smallest first, all the way along
  • B Write a big number, then a small one, turn and turn about
  • C Write every number close to every other number
  • D Write all the big numbers together at one end of the row
Show answer
Answer: Write a big number, then a small one, turn and turn about
Why:

Alternating puts a winner in every second box, which is the most allowed.

Q16 A number line runs 3000, 3200, 3400 and onwards. One step on this line is worth ____. beginner
  • A 2
  • B 200
  • C 20
  • D 2000
Show answer
Answer: 200
Why:

Each label is 200 more than the label before it.

Q17 A number line is labelled 45670 at one end and 45680 at the other, with four blank marks in between. What is one step worth? intermediate
  • A 1
  • B 5
  • C 10
  • D 2
Show answer
Answer: 2
Why:

The difference of 10 is shared among five equal gaps.

Q18 Why does a number line make it easy to compare 5030 with 5300? intermediate
  • A Because the digits of the two numbers are the same ones
  • B Because the bigger number stands further to the right
  • C Because a line always puts the smaller number first in the list
  • D Because both numbers can be rounded to the same thousand
Show answer
Answer: Because the bigger number stands further to the right
Why:

A line turns size into position, so the eye does the comparing.

Q19 Match each idea with its home: (i) a peak in a row of children, (ii) a supercell in a table. advanced
  • A (i) says 2 and (ii) beats one neighbour only
  • B (i) says 0 and (ii) beats every neighbour it has
  • C (i) says 1 and (ii) holds the smallest number present
  • D (i) says 0 and (ii) sits at an end of the row
Show answer
Answer: (i) says 0 and (ii) beats every neighbour it has
Why:

Both ideas describe something that beats everything immediately beside it.

Q20 The marks on a line read 86,705 then 87,705. Somebody says each step is worth 100. Are they right? advanced
  • A No, the step is 1000, since that is the difference between the labels
  • B Yes, because only the hundreds digit has changed between the two labels
  • C Yes, because the numbers are close to each other
  • D No, the step is 10, since the last digits match
Show answer
Answer: No, the step is 1000, since that is the difference between the labels
Why:

Subtract one label from the next and the gap is a thousand.

Important short questions (6)

Explain in your own words what a child's number reports in the lining-up game.

It counts how many of the people standing right beside that child are taller than the child is.

Why can the two children at the ends of a row never call out 2?

Each of them has a neighbour on one side only. Counting two taller neighbours needs a person on both sides.

Four children of heights 122, 130, 145 and 138 centimetres stand in that order. Write down what each calls out.

They call out 1, 1, 0 and 1. The 145 cm child beats both neighbours, and each of the others has exactly one taller neighbour.

Give one reason why a table can never have two coloured boxes touching each other.

Each box would need a number greater than the other box holds. That cannot happen with two different numbers.

A row has nine boxes. What is the greatest number of supercells it can hold, and how would you arrange it?

Five. Put a large number in the first box and then in every second box after it, with small numbers in between.

A number line shows 15,077 and 15,078 next to each other. What is one step worth, and what would the next three marks read?

One step is worth 1. The next marks read 15,079, then 15,080, then 15,081.

Long answer questions (3)

Think and write: a friend claims that five children of different heights could all call out 1. Show him that this is impossible, and describe a list that really can happen.

One of the five is taller than the other four. Nobody standing beside that child can be taller, so that child has to call out 0. A list of five ones therefore cannot happen, whoever stands where. A list that does work is 1, 1, 0, 1, 1. Arrange the children with the tallest in the middle, the next two on either side of her, and the two shortest at the ends. Each of the four outer children then has exactly one taller neighbour.

Think and write: explain how you would fill a row of seven boxes so that it holds as many supercells as it possibly can, and say why you cannot do better.

I would put a large number in the first box, a small number in the second, and carry on turn by turn. That colours the first, third, fifth and seventh boxes, so four supercells appear. I cannot do better, because two coloured boxes are never allowed to touch. Each one would have to beat the other, which no pair of numbers manages. Leaving a gap after every coloured box means at most four of seven can win.

Think and write: two number lines look exactly alike, yet one runs from 3000 to 4000 and the other from 45,670 to 45,680. Explain how a reader tells them apart and how each blank mark is filled.

The drawing carries no information by itself. Only the labels do. I would read the two labelled marks and take one away from the other. Then I would count the equal gaps lying between those marks and share the difference out among them. On the first line the difference is 1000 over five gaps, so each step is worth 200. On the second the difference is 10 over five gaps, so each step is worth 2. After that every blank mark can be filled by adding one step at a time.

Flashcards (15)

In the lining-up game, what does a child's number count?
The neighbours standing beside that child who are taller than the child is.
Why can a child at the end of a row never call out 2?
That child has one neighbour only, so at most one taller person can be counted.
Which child in a row always calls out 0?
The tallest one, because no neighbour of theirs can be taller.
Can every child in a row of five call out 0?
No. The shortest child always has a taller neighbour, so a zero is impossible there.
Is the list 1, 1, 1, 1, 1 possible for five children of different heights?
No, because the tallest child must call out 0 wherever she stands.
What does a 2 in the list tell you about that child?
That child is shorter than both neighbours, so the row dips there.
When is a box in a table called a supercell?
When its number is greater than the number in every box touching it.
How many neighbours does a box at the end of a row have?
One. So it has to beat a single number to become a supercell.
In the row 412, 806, 375, 940, 268, 719, 153, which boxes are supercells?
806, 940 and 719.
Why can two supercells never sit side by side?
Each would have to be greater than the other, and no pair of numbers can do that.
What is the largest number of supercells a row of nine boxes can hold?
Five, by colouring the first box and then every second box after it.
Is the box holding the biggest number in a table always a supercell?
Yes. It beats every other number in the table, so it beats its neighbours too.
What does the step of a number line mean?
The amount added on each time you move from one mark to the next one.
Two labelled marks read 3000 and 4000 with four blank marks between. What is one step worth?
200, because the difference of 1000 is shared out among five equal gaps.
Why does a number line make comparing two numbers easy?
Size becomes position, so the bigger number simply stands further to the right.

Play this topic

  • Idea and meaning
  • Possible or impossible?
  • Fact or myth?
  • Unscramble the word
  • Label a blank number line

Playing with Digits

Digits can be added, reversed and rearranged. Digit sums group very different numbers together, palindromes read the same both ways, and one stubborn routine drags every four-digit number to 6174.

What you will be able to do

  • I can work out a digit sum and find the smallest or largest number that gives one.
  • I can test whether a number is a palindrome and count how many palindromes exist of a given length.
  • I can carry out the reverse-and-add game and say how many rounds it took.
  • I can run Kaprekar's routine on a four-digit number and reach 6174.

Key points

  • There are 9 one-digit numbers, 90 two-digit numbers, 900 three-digit numbers and 9000 four-digit ones.

  • A digit sum adds the digits and ignores place value, so 89, 764 and 98,000 all come to 17.

  • A three-digit number whose digits run on has a digit sum of three times its middle digit.

  • Writing 1 to 100 uses the digit 4 twenty times, ten in the units place and ten in the tens.

  • A palindrome reads the same from either end, and there are 90 three-digit ones.

  • Reverse and add always reaches a palindrome from a two-digit start, though 89 needs 24 rounds.

  • Whether every three-digit start reaches a palindrome is still unknown, and 196 is the doubtful case.

  • Kaprekar's routine takes any four-digit number with two different digits to 6174.

Full explanation

Arjun counts the numbers

Arjun writes numbers in his book, starting at 1. He wonders how many numbers there are of each size. One-digit numbers run from 1 to 9, so there are nine of them. Two-digit numbers run from 10 to 99, and there are ninety. Three-digit numbers run from 100 to 999, and there are nine hundred. Each step up multiplies the count by ten. Five-digit numbers come to ninety thousand.

Adding the digits instead of using them

Here is a different thing to do with a number. Ignore what it is worth and just add its digits. The digits of 89 add to 17. The digits of 764 also add to 17. So do the digits of 98,000. These three numbers are miles apart in size, yet they share one digit sum.

Hunting for the smallest and the largest

Suppose you want a digit sum of 17 and the smallest number that gives it. Use as few digits as you can, and make the last digit as large as possible. That gives 89. Now ask for the largest five-digit number with the same digit sum. Load the front digits and leave the rest at zero, which gives 98,000.

A pattern in consecutive digits

Try three-digit numbers whose digits run on, like 234 or 567. Add the digits of 234 and you get 9. Add the digits of 567 and you get 18. Each answer is three times the middle digit. That is no accident. One digit is one less than the middle and one is one more, so the two changes cancel out.

Counting a digit rather than a number

Rekha writes out all the numbers from 1 to 100 and asks how many times she has written the digit 4. In the units place a 4 appears ten times, at 4, 14, 24 and so on. In the tens place it appears ten more times, all through the forties. So she has written it twenty times.

Numbers that read the same either way

Some numbers are unchanged when you read them backwards. 66 is one. So are 848 and 1111. These are called palindromes. Checking one is easy: pair the first digit with the last, the second with the second last, and so on. Every pair must match. In a number with an odd count of digits, the middle digit has no partner and can be anything.

How many palindromes are there?

Count the three-digit ones. The first digit may be any of 1 to 9, and the last is forced to copy it. The middle digit is free and may be any of 0 to 9. So there are ninety. Five-digit palindromes work the same way, with two free middle digits, and there are nine hundred of them.

Reverse and add

Now a game. Take a number, reverse it, and add the two together. If the answer is a palindrome, stop. If not, do the same thing again. Start with 23 and one round is enough: 23 plus 32 gives 55. Start with 57 and it takes two rounds, reaching 132 and then 363.

Some numbers keep you waiting

Start at 68 and you need three rounds, passing through 154 and 605 before landing on 1111. Start at 89 and the patience required is astonishing. It takes twenty-four rounds, and the palindrome at the end has thirteen digits. Nobody could guess that from looking at 89.

What nobody has settled

Every two-digit starting number does reach a palindrome in the end. Three-digit numbers are a different story, and this one is not finished. Mathematicians do not know whether every three-digit start reaches a palindrome. The number 196 is the famous doubtful case. Computers have run it for a very long time without a palindrome appearing, and people suspect it never will. Suspecting is not the same as knowing.

A teacher from Devlali

D.R. Kaprekar earned his living teaching mathematics at a state school in the town of Devlali, in Maharashtra. He spent his spare hours playing with numbers and found patterns nobody had noticed before. In 1949 he came across something very strange indeed while fiddling with four-digit numbers.

His routine, step by step

Pick a four-digit number with at least two different digits. Rearrange its digits to make the largest number you can, and call that A. Rearrange them again to make the smallest, and call that B. Work out A minus B. Then start over with the answer, and keep going.

Watching 2059 settle down

The digits of 2059 give a largest of 9520 and a smallest of 0259, which is just 259. Taking 259 from 9520 leaves 9261. Round two turns 9261 into 8352. Round three turns 8352 into 6174. Try a fourth round and nothing moves: the largest is 7641, the smallest is 1467, and the difference is 6174 all over again.

Why the routine has to stop somewhere

That number 6174 is called the Kaprekar constant. Every four-digit start with two different digits reaches it, and never in more than seven rounds. The warning about two different digits matters. A number like 5555 gives the same largest and smallest, so the difference is zero and there is nothing left to work with.

The same idea with three digits

Three-digit numbers have a constant of their own. Begin at 325 and the routine gives 297, then 693, then 594, then 495. From there it repeats 495 for ever. So the three-digit routine settles as well, just at a different resting place.

Concepts and terms

Digit sum

The total you get by adding the digits of a number, treating each one as a plain figure rather than a value. Place value is thrown away, which is why 89 and 98,000 share the digit sum 17.

Palindrome

A number whose digits are unchanged when the whole thing is read backwards, such as 848 or 1111. Pair the first digit with the last and work inwards. A middle digit with no partner is free.

Reverse and add

A routine: reverse a number, add the reversal to the original, and repeat until a palindrome appears. From a two-digit start it always finishes. From a three-digit start nobody knows whether it always does.

Kaprekar constant

The number 6174. Make the largest and smallest arrangements of a four-digit number, subtract, and repeat. Provided at least two of the digits differ, the working always arrives at 6174 and then sticks there.

Watch out!

Myth or reality

Case Study

Scenario:

A class notices a number plate reading 2059 and is asked to make the largest and smallest numbers from those digits. The largest comes quickly: 9520. The smallest causes an argument. Arjun writes 0259 and Nita says that is not a four-digit number at all. The class tests it by reading it aloud, and it says two hundred and fifty-nine. So the zero cannot lead. The smallest four-digit arrangement is 2059, the plate itself. Arjun sees why. A leading zero does not change the value, so it quietly turns a four-digit number into a three-digit one.

Analysis:

The argument is about what a digit in front actually does. A leading zero adds a symbol and no value, so the number shrinks a place.

Activity:

Take a four-digit number plate with a zero in it. Write the largest and smallest four-digit numbers you can make.

A digit workshop at home

Title:

A digit workshop at home

What You Notice:

Your birth year always reaches 6174, and so does everybody else's, though the number of rounds differs from person to person. The reverse-and-add game can finish at once or drag on for a surprising number of rounds.

Did you know

Kaprekar did all of his exploring while holding down a full timetable at a state-run school in the town of Devlali.

No four-digit number with two different digits needs more than seven rounds of the routine before it reaches 6174.

Palindromes turn up outside mathematics too. Malayalam is a language whose name reads the same both ways.

Memory tricks

Testing a palindrome — Outside in, pair by pair — Compare the outermost digits, then step inwards. One mismatch anywhere ends the test. A lone middle digit never needs checking.

The order of Kaprekar's routine — Biggest minus smallest, then go again — Arrange the digits high to make A, arrange them low to make B, and subtract. Feed the answer straight back in.

Practice MCQs with answers (20)

Q1 How many four-digit numbers are there? beginner
  • A 900
  • B 10,000
  • C 90,000
  • D 9,000
Show answer
Answer: 9,000
Why:

They run from 1000 to 9999, which is nine thousand numbers.

Q2 The digit sum of 764 is ____. beginner
  • A 13
  • B 16
  • C 17
  • D 20
Show answer
Answer: 17
Why:

Adding 7, 6 and 4 gives seventeen.

Q3 Priya wants the smallest number whose digits add to 17. What should she do first? intermediate
  • A Use as many digits as she can, all of them small
  • B Use as few digits as she can, with the largest at the end
  • C Start from 17 and keep adding ten to it
  • D Pick any number and cross out digits until they add to 17
Show answer
Answer: Use as few digits as she can, with the largest at the end
Why:

Fewer digits means a smaller number, and 89 is the result.

Q4 Three of these numbers have a digit sum of 17. Which one does not? intermediate
  • A 89
  • B 764
  • C 9,710
  • D 5,432
Show answer
Answer: 5,432
Why:

The digits of 5,432 come to 14, while the other three each come to 17.

Q5 The digits of 345 run on one after another. Its digit sum is three times which digit? intermediate
  • A The first
  • B The middle
  • C The last
  • D None, the rule fails here
Show answer
Answer: The middle
Why:

One digit is one below the middle and the other is one above, so they cancel.

Q6 Writing out the numbers from 1 to 100, how many times is the digit 4 written? intermediate
  • A Ten
  • B Nineteen
  • C Twenty
  • D Forty
Show answer
Answer: Twenty
Why:

Ten appearances in the units place and ten through the forties.

Q7 Reading a number backwards leaves its digits exactly as they were. Such a number is called a ____. beginner
  • A constant
  • B multiple
  • C sequence
  • D palindrome
Show answer
Answer: palindrome
Why:

That is exactly what the word palindrome means.

Q8 Which of these four numbers is a palindrome? beginner
  • A 4,562
  • B 7,337
  • C 1,232
  • D 8,910
Show answer
Answer: 7,337
Why:

Its outer digits are both 7 and its inner digits are both 3.

Q9 How many three-digit palindromes are there altogether? intermediate
  • A Nine
  • B Nine hundred
  • C One thousand
  • D Ninety
Show answer
Answer: Ninety
Why:

Nine choices for the first digit and ten for the middle one.

Q10 In the reverse-and-add game, what do you do with the answer if it is not a palindrome? beginner
  • A Put it through the same steps again
  • B Go back and start from a different number
  • C Subtract the reversal from it instead
  • D Stop, because the game has failed
Show answer
Answer: Put it through the same steps again
Why:

The routine simply repeats on whatever answer it produces.

Q11 Start the reverse-and-add game at 57. What does the first round give? intermediate
  • A 75
  • B 112
  • C 132
  • D 363
Show answer
Answer: 132
Why:

Adding 57 and 75 gives 132, which is not yet a palindrome.

Q12 Which statement about the reverse-and-add game is true? advanced
  • A Every two-digit start reaches a palindrome in one round
  • B Every three-digit start has been proved to reach a palindrome
  • C Every two-digit start reaches a palindrome in the end
  • D The game has been proved to fail for 196
Show answer
Answer: Every two-digit start reaches a palindrome in the end
Why:

Two-digit starts always finish, though 89 takes twenty-four rounds; the three-digit case is unsettled.

Q13 What do mathematicians currently say about 196 and the reverse-and-add game? advanced
  • A Nobody has settled it, and a palindrome is suspected never to appear
  • B It has been proved that 196 does give a palindrome eventually
  • C It has been proved that 196 never gives a palindrome
  • D Nobody has settled it, and a palindrome is expected within a few rounds
Show answer
Answer: Nobody has settled it, and a palindrome is suspected never to appear
Why:

Long computer searches have found nothing, but a search is not a proof.

Q14 Where did D.R. Kaprekar teach? beginner
  • A A state school in the town of Devlali, Maharashtra
  • B A college of engineering in Pune, Maharashtra
  • C A state school in the town of Nashik, Gujarat
  • D A research institute for mathematics in Mumbai, Maharashtra
Show answer
Answer: A state school in the town of Devlali, Maharashtra
Why:

He was a schoolteacher, not a research worker.

Q15 Match the routine with its resting place: (i) four-digit Kaprekar, (ii) three-digit Kaprekar. intermediate
  • A (i) 495 and (ii) 6174
  • B (i) 6174 and (ii) 495
  • C (i) 6174 and (ii) 1089
  • D (i) 1089 and (ii) 495
Show answer
Answer: (i) 6174 and (ii) 495
Why:

Four digits settle at 6174 and three digits settle at 495.

Q16 The digits of 2059 make a largest of 9520. What is the smallest number they make? intermediate
  • A 2059
  • B 0259, which is 259
  • C 5902
  • D 9250, putting the zero right at the end
Show answer
Answer: 0259, which is 259
Why:

The zero goes to the front, so the number is really 259.

Q17 Consider these statements about digits and digit sums. I. There are 90 two-digit numbers. II. There are 100 three-digit numbers. III. 89, 764 and 98,000 all have a digit sum of 17. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are correct. II is not: there are 900 three-digit numbers, from 100 to 999.

Q18 Assertion: A three-digit number whose digits run on has a digit sum of three times its middle digit. Reason: Its digits are the middle one less one, the middle one, and the middle one more one. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true, and the reason is the whole of it: (m-1) + m + (m+1) comes to 3m. So 456 adds to 15, which is 3 times 5.

Q19 Once the routine reaches 6174, what happens on the next round? beginner
  • A It produces 6174 again
  • B It produces 495
  • C It produces zero
  • D It produces a larger number each time
Show answer
Answer: It produces 6174 again
Why:

Taking 1467 from 7641 leaves 6174 once more.

Q20 Which of these is a fair thing to say about mathematics after this topic? advanced
  • A Every question about numbers has been answered by now
  • B A question that is easy to ask is always easy to answer
  • C Questions are only real once a computer has checked them
  • D Some questions that are easy to ask are still open
Show answer
Answer: Some questions that are easy to ask are still open
Why:

The 196 question can be explained in a minute and remains unsolved.

Important short questions (6)

Explain what a digit sum is and why 89 and 98,000 share one.

A digit sum adds the digits and ignores what each is worth. The digits of both numbers are 8 and 9, plus zeros, so both come to 17.

How many times does the digit 4 appear when the numbers 1 to 100 are written out? Show your reasoning.

Twenty times. It appears ten times in the units place and ten more times through the forties, and nothing else contributes.

Explain how to check quickly whether 7,337 is a palindrome.

Pair the outer digits and then the inner ones. Both outer digits are 7 and both inner digits are 3, so it reads the same either way.

Play one round of reverse and add starting from 23, and say what happens.

Reversing 23 gives 32, and the two add to 55. That is a palindrome, so the game stops after a single round.

What is currently known about 196 and the reverse-and-add game? Be careful with your wording.

Nothing has been settled. Very long computer searches have produced no palindrome, so people suspect there is none, but that has never been proved.

Why must a four-digit number have at least two different digits before Kaprekar's routine is worth starting?

If all four digits match, the largest and smallest arrangements are the same number. Their difference is zero, so there is nothing to carry forward.

Long answer questions (3)

Think and write: run Kaprekar's routine on 2059, setting out each round, and say what the routine tells you about four-digit numbers in general.

The digits of 2059 make a largest of 9520 and a smallest of 0259, which is 259. Taking 259 from 9520 leaves 9261. In round two the largest is 9621 and the smallest is 1269, and the difference is 8352. In round three the largest is 8532 and the smallest is 2358, and the difference is 6174. A fourth round changes nothing at all. The routine shows that every four-digit number with two different digits is pulled to 6174, and never takes more than seven rounds to get there.

Think and write: a classmate writes that 196 never gives a palindrome. Explain why you would ask him to change that sentence, and write a better one.

His sentence states something as a fact when nobody has shown it. Computers have carried the reverse-and-add game on 196 for an enormous number of rounds and no palindrome has turned up. That is strong evidence and it is not a proof. A search can only tell you what has not happened so far. A better sentence would be that 196 is suspected never to give a palindrome, and that the question is still open. Being honest about what is unknown is part of mathematics.

Think and write: explain how you would find the largest five-digit number with a digit sum of 17, and compare your method with finding the smallest number with the same digit sum.

To make a five-digit number large I care most about the leading digit, so I give it the biggest share I can, which is 9. That leaves 8 to place, and the next digit takes all of it. The last three digits are then zeros, giving 98,000. To make a number small I want as few digits as possible instead, so I use two digits and put the larger one at the back. That gives 89. The two hunts pull in opposite directions, one loading the front and one shortening the number.

Flashcards (15)

How many three-digit numbers are there altogether?
Nine hundred, running from 100 up to 999.
What does the digit sum of a number mean?
The total of its digits, added as plain figures with place value ignored.
What is the smallest number whose digits add to 17?
89, because two digits are the fewest that will do and 9 is the largest last digit.
What is the largest five-digit number whose digits add to 17?
98,000. The front digits are loaded and the rest are left at zero.
Why does 567 have a digit sum of 18?
Its digits run on, so the sum is three times the middle digit, and 3 times 6 is 18.
How many times is the digit 4 written when you write out 1 to 100?
Twenty times, ten in the units place and ten more through the forties.
How do you test whether a number is a palindrome?
Pair the outermost digits and work inwards. Every pair must match.
How many three-digit palindromes are there?
Ninety. The first digit has nine choices, the middle has ten, and the last copies the first.
Describe the reverse-and-add game in one sentence.
Reverse the number, add it to the original, and repeat until a palindrome appears.
How many rounds does the reverse-and-add game need starting from 68?
Three rounds, passing through 154 and 605 before it reaches 1111.
Is it known whether every three-digit number reaches a palindrome by reversing and adding?
No. It is an open question, and 196 is the case people doubt.
Who was D.R. Kaprekar?
A schoolteacher of mathematics from the town of Devlali in Maharashtra, who hit on the routine in 1949.
Set out the steps of Kaprekar's routine.
Make the largest arrangement, make the smallest, subtract the smaller from the larger, and repeat.
Why must a four-digit number have at least two different digits for the routine to work?
Otherwise the largest and smallest arrangements match, the difference is zero, and nothing is left.
Where does Kaprekar's routine settle for three-digit numbers?
At 495, which then repeats itself for ever.

Play this topic

  • Term and meaning
  • Settled or still open?
  • Fact or myth?
  • Finish the sentence
  • One round of Kaprekar's routine

Numbers in Time, and Sums in Your Head

Clocks and calendars are full of number patterns, and large sums often come apart into friendly pieces. Both reward looking before calculating.

What you will be able to do

  • I can test a clock reading or a date to see whether it is a palindrome.
  • I can build the largest and smallest numbers from a set of digits and compare them.
  • I can reach a target total by combining a few given pieces, repeating a piece where I need to.
  • I can add a pattern of numbers quickly by grouping equal values instead of adding one by one.

Key points

  • A clock reading is tested for a palindrome exactly like a number, once the colon is ignored.

  • A 12-hour clock shows 57 palindromic times, six in each single-digit hour and one each at 10, 11 and 12.

  • A date written as day, month and year can read the same both ways, as 21/02/2012 does.

  • A common year is one day longer than 52 weeks, so every date moves on a weekday the following year.

  • Sorting four digits downwards gives the largest number and upwards gives the smallest.

  • When building a total from given pieces, a piece may be used as many times as you like.

  • Allowing subtraction as well as addition makes many totals much quicker to reach.

  • A four-digit number plus a two-digit number can never reach six digits, whatever you choose.

Full explanation

A clock with something to say

Nisha glances at the wall clock and sees 5:55. A minute later the pattern is gone. She starts watching for readings that look special. Some repeat a digit, like 11:11. Others read the same backwards, like 3:03 or 12:21. A clock face is only a pair of numbers, and yet it throws up patterns all day long.

Testing a time for a palindrome

Ignore the colon and look at the digits alone. The reading 3:03 gives 303, which reads the same either way. The reading 12:21 gives 1221, which also passes. The reading 4:15 gives 415, and backwards that is 514, so it fails. The test is exactly the one you use on a plain number.

How many such times are there?

Take an hour with a single digit, say 3. The reading is 3 then two minute digits, so the last digit has to be a 3 as well. The first minute digit may be 0, 1, 2, 3, 4 or 5. That gives six times in every such hour, and there are nine of those hours. The hours 10, 11 and 12 contribute one each. The total is fifty-seven.

Dates can do it too

A date written as day, month and year makes an eight-digit string. The date 21/02/2012 gives 21022012, and that reads the same from either end. So does 10/02/2001. Such dates are rare, so people notice them and remember them.

Will a calendar ever come round again?

Jaspreet wonders why a new calendar is printed every year. The answer is that the days slide. A year of 365 days is fifty-two weeks and one day over, so every date shifts on by one weekday. A leap year shifts it by two. A calendar can be used again only by a year that starts on the same weekday and is of the same kind, leap or common.

Building the biggest and the smallest

Give yourself four digits, say 8, 1, 5 and 3. Sort them downwards for the largest number, 8531. Sort them upwards for the smallest, 1358. Their difference is 7173 and their sum is 9889. Change the digits you start from and both answers change, which makes a good puzzle for a friend.

Sums you can do without writing

A large addition is often easier in the head than on paper, provided you break it up sensibly. Suppose you have the pieces 30,000, 9,000, 1,200 and 200 to build with. You may take any piece as often as you like. To reach 40,600, take 30,000 and 9,000 and 1,200, then take 200 twice.

Why repeating a piece is allowed

Children often assume each piece is used once and then give up. Nothing in the rules says that. Reaching 40,600 needs the 200 twice. Once you see that a piece can come back, many more totals fall into place, and a short set of pieces goes a long way.

Taking away as well as adding

Now allow subtraction too. Some totals are much easier that way round. To reach 29,700 you could hunt for pieces that add up to it, or you could start from 30,000, take away 500 and put 200 back. Working down from above is often the quicker route.

How many digits does the answer have?

A five-digit number added to another five-digit number sometimes gives five digits and sometimes six. Try 10,000 and 10,000, which gives 20,000. Now try 99,999 twice, which gives 199,998. So the answer is sometimes five digits and sometimes six, and the only way to know is to look.

Some answers are simply out of reach

Other cases can be ruled out at once. A four-digit number plus a two-digit number can never have six digits. The largest you can manage is 9,999 plus 99, which is 10,098, and that has five. In the same way, a five-digit number take away a two-digit number never drops to three digits.

Examples worth keeping

It helps to have one clean example of each kind in your notebook. Adding 54,321 and 67,890 gives 122,211, which is two five-digit numbers making six digits. Taking 40,905 from 41,208 leaves 303, which is two five-digit numbers making three digits. Writing your own examples is better practice than reading mine.

Adding a figure the quick way

A pattern of numbers can be added one at a time, but that is slow and mistakes creep in. Look for equal numbers instead and count them. Four rows of six twenty-fives is twenty-four twenty-fives, and 24 x 25 = 600. One multiplication has replaced twenty-three additions.

Splitting a figure into groups

Some patterns hold two different numbers. Deal with each group on its own and add at the end. Twelve fifteens come to 180, because 12 x 15 = 180. Eight thirty-fives come to 280. Adding those two totals gives 460. The order in which you group them does not change the answer, so choose whichever grouping you find easiest to see.

Concepts and terms

Palindromic time

A clock reading whose digits are unchanged when read backwards, such as 3:03 or 12:21. Drop the colon first and treat what is left as an ordinary number. A 12-hour clock shows fifty-seven of them.

Largest and smallest from given digits

Sorting a set of digits downwards builds the largest number they can make, and sorting them upwards builds the smallest. A zero among them moves to the front of the smallest and shortens it.

Building a total from pieces

Reaching a target by combining a short list of given numbers. Each piece may be taken more than once, and allowing subtraction as well as addition opens up totals that addition alone cannot reach easily.

Grouping to add quickly

Counting how many times each value appears in a pattern and multiplying, instead of adding the numbers one after another. Twelve fifteens is one multiplication rather than eleven additions.

Watch out!

Myth or reality

Fatima plans the school bell

Scenario:

Fatima helps her teacher set the bell times for the school day in Bhopal. The first period begins at 9:00 in the morning. Each period runs for forty minutes and there is no gap between them. Fatima writes out the starting time of every period in a list. Partway down she notices that one of the times reads the same backwards. Her teacher then asks her a second question. The school wants to reuse the same printed timetable card next year. Fatima says that the times will be fine but the dates and weekdays printed beside them will not, because a year does not divide evenly into whole weeks. She works out both answers in her notebook.

Analysis:

Number patterns and calendar arithmetic both turn up in an ordinary school day, and both can be settled by careful counting rather than by guesswork.

Activity:

Write out the start times of six lessons in your own school and mark any that read the same backwards.

Did you know

A common year runs one day past fifty-two whole weeks, which is why your birthday lands on a new weekday each year.

Palindromic dates cluster in certain years and are missing altogether from others, depending on how the digits of the year fall.

Memory tricks

Testing a clock reading — Drop the colon, read it back — The colon is punctuation and carries no value. What is left is a plain number, and the usual palindrome test applies.

Building from pieces — Any piece, any number of times — Nothing limits you to one go with each piece. Remembering this is what unlocks totals that look impossible at first.

Practice MCQs with answers (20)

Q1 Which of these clock readings is a palindrome? beginner
  • A 5:35
  • B 4:15
  • C 7:20
  • D 9:41
Show answer
Answer: 5:35
Why:

Its digits are 535, which reads the same from either end.

Q2 To test a time for a palindrome you should first ____. beginner
  • A ignore the colon and look at the digits
  • B convert the time to the 24-hour system
  • C round the minutes to the nearest ten
  • D add the hour digits to the minute digits
Show answer
Answer: ignore the colon and look at the digits
Why:

The colon is punctuation, so the digits are what matter.

Q3 How many palindromic times appear on a 12-hour clock altogether? intermediate
  • A Twelve
  • B Twenty-four
  • C Fifty-seven
  • D Sixty
Show answer
Answer: Fifty-seven
Why:

Nine hours contribute six each, and 10, 11 and 12 contribute one each.

Q4 In the hour beginning at 6 o'clock, how many palindromic times occur? advanced
  • A One
  • B Three
  • C Ten
  • D Six
Show answer
Answer: Six
Why:

The minutes must end in 6, and the first minute digit may be 0 to 5.

Q5 Which date written as digits reads the same from either end? intermediate
  • A 12/11/2013
  • B 03/04/2005
  • C 19/08/2019
  • D 21/02/2012
Show answer
Answer: 21/02/2012
Why:

Its eight digits are 21022012, unchanged when reversed.

Q6 Why does a date fall on a different weekday next year? intermediate
  • A Because months have different lengths
  • B Because a common year is one day longer than fifty-two weeks
  • C Because the calendar is reprinted every year with a new design
  • D Because a week sometimes has eight days
Show answer
Answer: Because a common year is one day longer than fifty-two weeks
Why:

That extra day pushes every date on by one weekday.

Q7 A calendar may be reused by a later year only if that year starts on the ____ weekday and is of the same kind. advanced
  • A next
  • B previous
  • C same
  • D opposite
Show answer
Answer: same
Why:

Both the starting weekday and the leap or common status must match.

Q8 What is the largest four-digit number that can be made from the digits 8, 1, 5 and 3? beginner
  • A 8135
  • B 8531
  • C 8513
  • D 1358
Show answer
Answer: 8531
Why:

Sorting the digits downwards puts the 8 in front, then 5, then 3, then 1.

Q9 From those same four digits, what is the difference between the largest and the smallest number? intermediate
  • A 7173
  • B 7371
  • C 8531
  • D 9889
Show answer
Answer: 7173
Why:

Taking 1358 from 8531 leaves 7173.

Q10 Which pair matches? (i) the sum of those two numbers, (ii) their difference. intermediate
  • A (i) 7173 and (ii) 9889
  • B (i) 9889 and (ii) 7173
  • C (i) 9889 and (ii) 8531
  • D (i) 8531 and (ii) 1358
Show answer
Answer: (i) 9889 and (ii) 7173
Why:

They add to 9889 and differ by 7173.

Q11 You may build totals from the pieces 30,000, 9,000, 1,200 and 200. How is 40,600 reached? intermediate
  • A By using each of the four pieces exactly once
  • B By using 30,000 twice and 1,200 once
  • C It cannot be reached from these pieces
  • D By using 30,000, 9,000, 1,200 and then 200 twice
Show answer
Answer: By using 30,000, 9,000, 1,200 and then 200 twice
Why:

The last four hundred needs the 200 piece taken a second time.

Q12 Which statement about building totals from pieces is true? beginner
  • A A piece may be used only once in any total
  • B Subtraction is never allowed, only addition
  • C A piece may be used as many times as you like
  • D Every total between the pieces can always be reached
Show answer
Answer: A piece may be used as many times as you like
Why:

Repeating a piece is what makes many targets reachable.

Q13 Starting from 30,000, which working reaches 29,700? intermediate
  • A Add 500, then take away 200
  • B Take away 500, then add 200
  • C Take away 300, then take away 200
  • D Add 700, then take away 200
Show answer
Answer: Take away 500, then add 200
Why:

Thirty thousand less five hundred is 29,500, and two hundred more is 29,700.

Q14 A four-digit number is added to a two-digit number. The answer can have six digits: always, sometimes or never? advanced
  • A Always
  • B Sometimes
  • C Never
  • D Only when both are even
Show answer
Answer: Never
Why:

The largest such sum is 9,999 plus 99, which is 10,098 and has five digits.

Q15 A five-digit number is added to another five-digit number. How many digits does the answer have? intermediate
  • A Always five
  • B Five or six, depending on the numbers
  • C Always six
  • D Four, five or six, depending on the sum
Show answer
Answer: Five or six, depending on the numbers
Why:

Two ten-thousands give five digits, while 99,999 twice gives six.

Q16 Consider these statements about palindromes in time and in numbers. I. A clock reading is tested for a palindrome once the colon is ignored. II. A 12-hour clock shows 12 palindromic times. III. Sorting four digits downwards gives the largest number they make. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are correct. II is not: a 12-hour clock shows 57, six in each single-digit hour and one each at 10, 11 and 12.

Q17 Four rows of six twenty-fives are to be added. What is the quickest correct method? intermediate
  • A Add the twenty-fives one at a time down each row
  • B Add the four row totals and then divide by six
  • C Multiply 25 by 4 and stop there
  • D Count twenty-four of them and multiply by 25
Show answer
Answer: Count twenty-four of them and multiply by 25
Why:

One multiplication settles it, since 24 x 25 = 600.

Q18 Assertion: A date falls one weekday later the following year. Reason: A common year is one day longer than 52 weeks. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true, and the reason is the arithmetic: 52 weeks is 364 days, so 365 leaves one day over.

Q19 Which of these statements is true? advanced
  • A A five-digit number minus a two-digit number can have three digits
  • B A four-digit number plus a two-digit number can have six digits
  • C A one-digit number plus a one-digit number can have three digits
  • D A five-digit number minus a five-digit number can have three digits
Show answer
Answer: A five-digit number minus a five-digit number can have three digits
Why:

Taking 40,905 from 41,208 leaves 303, which shows it happening.

Q20 Match each habit with the job it helps with: (i) drop the colon, (ii) count the equal values. beginner
  • A (i) testing a time, (ii) adding a pattern quickly
  • B (i) adding a pattern quickly, (ii) testing a time
  • C (i) testing a date, (ii) reusing a calendar
  • D (i) reusing a calendar, (ii) sorting digits
Show answer
Answer: (i) testing a time, (ii) adding a pattern quickly
Why:

One habit prepares a clock reading and the other speeds up a long addition.

Important short questions (6)

Explain how you decide whether a clock reading is a palindrome, using 12:21 as your example.

Drop the colon, which leaves the digits 1221. Read them from the other end and they are unchanged, so the time is a palindrome.

Why does each single-digit hour on a clock contain exactly six palindromic times?

The final minute digit has to copy the hour digit. The first minute digit can only be 0, 1, 2, 3, 4 or 5, which gives six choices.

Using the digits 9, 2, 6 and 4, write the largest and the smallest four-digit numbers and give their difference.

The largest is 9642 and the smallest is 2469. Their difference is 7173.

You may use the pieces 30,000, 9,000, 1,200 and 200 as often as you like. Show how to reach 40,600.

Take 30,000, then 9,000, then 1,200, and then the 200 piece twice over. Those five pieces together come to 40,600.

Explain why a four-digit number added to a two-digit number can never give a six-digit answer.

The largest four-digit number is 9,999 and the largest two-digit one is 99. Their sum is 10,098, which has only five digits, so nothing larger is possible.

A figure is made of twelve fifteens and eight thirty-fives. Find the total without adding one at a time.

Twelve fifteens come to 180 and eight thirty-fives come to 280. Adding those two group totals gives 460.

Long answer questions (3)

Think and write: explain why a 12-hour clock shows fifty-seven palindromic times, setting out your counting carefully.

Take an hour with one digit, such as 4. The reading has three digits, so the last one has to match the hour and be a 4. The first minute digit may be 0, 1, 2, 3, 4 or 5, since minutes stop below sixty. That gives six times in each such hour, and there are nine hours with a single digit, which makes fifty-four. The hours 10, 11 and 12 each have four digits, and only one arrangement works in each, giving 10:01, 11:11 and 12:21. Fifty-four and three together make fifty-seven.

Think and write: a classmate says that when you build a total from given pieces, each piece may be used only once, so 40,600 is impossible from 30,000, 9,000, 1,200 and 200. Reply to him.

His rule is one he has invented. Nothing in the puzzle says a piece is used up once it has been taken. Working with his rule, the four pieces come to 40,400, which does indeed fall short. Once the rule is dropped the target is easy. Take 30,000, then 9,000, then 1,200, and then the 200 twice. That reaches 40,600 exactly. The lesson is worth remembering, because a rule you add for yourself can make a simple problem look impossible.

Think and write: compare a claim that can be ruled out for ever with one that depends on the numbers chosen, using additions of your own.

Some claims can be settled by testing the extreme case alone. A four-digit number plus a two-digit number can never reach six digits, because even 9,999 plus 99 gives 10,098, which has five. Nothing bigger is available, so the case is closed. Other claims depend on the numbers. A five-digit number added to another sometimes gives five digits and sometimes six. Ten thousand twice comes to 20,000, which has five. Adding 99,999 to itself gives 199,998, which has six. So one claim is never, and the other is only sometimes.

Flashcards (15)

How do you test a clock reading for a palindrome?
Ignore the colon and read the digits backwards. If nothing changes, the time is a palindrome.
Is 12:21 a palindromic time?
Yes. Its digits are 1221, which reads the same from either end.
How many palindromic times does a 12-hour clock show?
Fifty-seven.
Why does each single-digit hour hold exactly six palindromic times?
The last minute digit must copy the hour, and the first minute digit may be 0 to 5.
Give an example of a date whose digits read the same both ways.
21/02/2012, which written out is 21022012.
Why is a fresh calendar printed every year?
A common year is one day longer than fifty-two weeks, so every date shifts to a new weekday.
How do you build the largest number from a set of digits?
Sort the digits downwards, putting the biggest at the front.
From the digits 8, 1, 5 and 3, what are the largest and smallest numbers?
The largest is 8531 and the smallest is 1358.
What is the difference between 8531 and 1358?
7173.
When you build a total from given pieces, how often may one piece be used?
As many times as you like. Nothing in the rules limits a piece to one use.
How would you reach 29,700 quickly from 30,000?
Take away 500, then put 200 back.
Can a four-digit number plus a two-digit number ever have six digits?
No. The largest possible sum is 10,098, which has five digits.
Does a five-digit number added to a five-digit number always give six digits?
No, only sometimes. Two ten-thousands give 20,000, which has five digits.
What is the quick way to add four rows of six twenty-fives?
Count them as twenty-four twenty-fives and multiply, which gives 600.
A pattern holds twelve fifteens and eight thirty-fives. What is its total?
460, from 180 for the first group and 280 for the second.

Play this topic

  • Idea and example
  • Always, sometimes or never
  • True or false?
  • Unscramble the word
  • Add a pattern the quick way

Estimating, and Winning Games

One simple rule leads to a problem nobody has solved, estimates answer questions that counting cannot, and a game of adding numbers turns out to have a rule hidden inside it.

What you will be able to do

  • I can build a Collatz run from any starting number and say how many steps it took.
  • I can explain why checking many numbers is not the same as proving something.
  • I can build an estimate in stages and say why I rounded where I did.
  • I can work out the winning strategy for an adding game by starting from the target.

Key points

  • The Collatz rule halves an even number and trebles an odd one before adding 1.

  • A power of two falls straight to 1, because halving it never produces an odd number.

  • The run from 27 climbs as high as 9,232 and takes 111 steps to finish.

  • Lothar Collatz suggested in 1937 that every whole number reaches 1, and nobody has proved it.

  • Checking billions of cases supports a belief but cannot settle it, since the whole numbers never end.

  • An estimate is built in stages, rounding on purpose so the next stage stays easy.

  • Counting for a minute and scaling up gives a usable estimate for a whole day.

  • In an adding game the safe numbers are spaced by one more than the largest jump allowed.

Full explanation

A rule anyone can follow

Here is a rule for making a run of numbers. Start anywhere you like. An even number gets cut in half. An odd number gets trebled, with one more added on. Then do the same to the answer. Nothing in that rule is hard. A child can follow it, and so can a computer.

Where the rule takes you

Start at 15. It is odd, so trebling and adding one gives 46. That is even, so halving gives 23. Carry on and the run climbs to 106, falls away, climbs again, and after seventeen steps arrives at 1. Start at 7 instead and it takes sixteen steps. Start at 32 and the whole run is a slide: 32, 16, 8, 4, 2, 1.

Powers of two fall straight down

A power of two is the easiest start of all. Halve it and you get another power of two. There is never an odd number to send you climbing again. So the run drops step by step and lands on 1 without a single detour.

Some runs wander a very long way

Not every start behaves so nicely. Begin at 27 and the run rises as high as 9,232 before it comes down. It takes a hundred and eleven steps to reach 1. Nothing about the number 27 warns you of that. Two starts that look alike can behave completely differently.

The part nobody has settled

In 1937 the German mathematician Lothar Collatz suggested that every whole number, followed by this rule, ends at 1. Mathematicians have worked on it ever since. Computers have checked an enormous stretch of numbers and every single one has reached 1. Even so, nobody has proved it for all numbers. It is still open, and among the best known questions of its kind anywhere.

Checking is not proving

The gap here is worth understanding. A computer can test the first many billions of starting numbers. That leaves infinitely many untested, because the whole numbers never run out. So a search can support a belief and can never finish the job. The honest sentence is that the conjecture is unproved.

When an exact number is not needed

Now put the puzzles aside for something practical. Your headteacher knows exactly how many children are on the roll. You do not, and you do not need to. Is it about two hundred, or about a thousand? That is an estimate, and for most purposes it is all anyone wants.

How an estimate is built

Maryam counts her own section: 38 children. The other two sections have 41 and 36. That comes to 115, so she calls her whole class about 120. Her school has five classes of a similar size. Five lots of 120 gives about 600. She has not counted a single child beyond her own section.

Rounding on purpose

Notice that Maryam rounded 115 up to 120 deliberately. An estimate is meant to be easy to carry in the head and easy to multiply. Carrying 115 through the next step would have given a false air of accuracy. An estimate that looks exact is worse than one that is plainly rough.

Estimating things you cannot count

Some quantities cannot be counted directly at all. How many breaths do you take in a day? Count them for one minute and suppose you get twenty. An hour has sixty minutes, and 20 x 60 = 1200. A day has twenty-four hours, and 1200 x 24 = 28800. The answer is rough, and it is far better than a shrug.

A game with a hidden rule

Now a game for two players. Each of you in turn puts 1, 2 or 3 on to a running total that begins at nothing. Whoever says 21 wins. Play it a few times and you will begin to feel that the first player has an advantage. There is a reason, and it is worth working out.

Working backwards from the win

Whoever says 21 wins, so 21 is a safe number. What about 17? From 17 your opponent can only reach 18, 19 or 20, and from any of those you can say 21. So 17 is safe too. Keep going down in fours: 13, 9, 5 and 1 are all safe. The first player says 1 and never lets go.

Why the gap is four

The largest jump allowed is 3. So whatever your opponent adds, you can add something that brings the pair of moves to exactly 4. Your rival adds 1 and you add 3. Your rival adds 3 and you add 1. Either way you move four along and stay on the safe list.

Changing the game changes the winner

Try a version where players add anything from 1 to 10 and the winner says 99. Now the gap is eleven, and the safe numbers are 11, 22, 33 and onwards to 99. The first player cannot reach 11 in one move, so the second player takes control. Here the second player wins with correct play.

Making the rule your own

The pattern is easy to state. Add one to the largest jump allowed, and that is the gap between safe numbers. If the target sits exactly on that gap, the second player wins. If it does not, the first player wins by opening on the remainder. Invent your own target and jump size and test it on a friend.

Concepts and terms

The Collatz rule

Halve the number if it is even; treble it and add one if it is odd; then repeat on the answer. Every run tried so far ends at 1, though some wander upwards a long way before they come down.

Conjecture

A statement somebody believes is true but nobody has proved. Collatz made his in 1937. A conjecture stays a conjecture however many examples agree with it, because examples cannot cover every case.

Estimate

A rough answer built on purpose, good enough for the question being asked. It is made in stages, with deliberate rounding at each stage so the working stays easy to carry in the head.

Safe number

A running total that hands your opponent a losing position in an adding game. The safe numbers are spaced by one more than the largest jump, and the target itself is always one of them.

Watch out!

Myth or reality

Estimating the school water tank

Scenario:

The tank on the roof of a school in Nagpur runs dry by the middle of the afternoon, and the headmaster asks the Class 6 children to work out why. Nobody can measure the tank, so the children estimate instead. Ritu counts the pupils at one water point during a single break and finds that about forty fill a bottle. There are three such points and three breaks in the day. A bottle holds about one litre. The children also allow roughly two hundred litres for the washrooms and the kitchen together. They write their working on the board in stages, rounding at each stage, and mark every figure with the word about so that nobody mistakes it for a measurement.

Analysis:

An estimate built in clear stages can answer a practical question that no available instrument can settle, provided each rounding is deliberate and openly recorded.

Activity:

Estimate how many litres your own household uses in a day by counting one bucket, then scaling up.

Invent a game and crack it

Title:

Invent a game and crack it

What You Notice:

The first five rounds look like luck and the last five do not. Whether the first or the second player wins is settled before anyone moves, by whether the target lands exactly on the gap.

Did you know

Lothar Collatz put his question forward in 1937, and it has resisted every attempt since.

The run that begins at 27 climbs to 9,232 before it turns, and needs 111 steps to reach 1.

The rule is often called the 3n plus 1 problem, after the step that every odd number has to take.

Memory tricks

Applying the Collatz rule — Even halve, odd climb — An even number is cut in two. An odd number is trebled and given one more. Those are the only two moves there are.

Finding a winning strategy — Start at the finish and walk back — Mark the target as safe, then step back by one more than the largest jump, again and again, until you reach the beginning.

Practice MCQs with answers (20)

Q1 Under the Collatz rule, what happens to an odd number? beginner
  • A It is halved
  • B It is trebled and given one more
  • C It is doubled and given one less
  • D It is left as it is
Show answer
Answer: It is trebled and given one more
Why:

Odd numbers are the ones that climb before they fall.

Q2 Apply the Collatz rule to 15. What comes next? beginner
  • A 7
  • B 16
  • C 30
  • D 46
Show answer
Answer: 46
Why:

Fifteen is odd, so trebling it gives 45 and one more gives 46.

Q3 Apply the Collatz rule to 46. What comes next? beginner
  • A 23
  • B 92
  • C 139
  • D 45
Show answer
Answer: 23
Why:

Forty-six is even, so it is halved.

Q4 Assertion: Checking billions of starting numbers does not settle the question. Reason: The whole numbers never end, so no amount of checking covers them all. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true, and the reason is why a proof is needed. The run from 27 alone climbs to 9,232 and takes 111 steps.

Q5 Why does a power of two never climb under the Collatz rule? intermediate
  • A Because it is always larger than 1
  • B Because halving it gives another power of two, which is even
  • C Because the rule leaves even numbers alone
  • D Because powers of two were left out of the conjecture entirely
Show answer
Answer: Because halving it gives another power of two, which is even
Why:

No odd number ever appears, and only odd numbers make the run climb.

Q6 The Collatz run that starts at 27 is famous because it ____. advanced
  • A never reaches 1 at all
  • B reaches 1 in only four steps
  • C repeats the number 27 for ever
  • D climbs to 9,232 and needs 111 steps
Show answer
Answer: climbs to 9,232 and needs 111 steps
Why:

A small start can take a very long and very high journey.

Q7 Who first put the Collatz conjecture forward, and in which year? beginner
  • A Lothar Collatz, in 1937
  • B D.R. Kaprekar, in 1949
  • C Lothar Collatz, in 1949
  • D Srinivasa Ramanujan, in 1913
Show answer
Answer: Lothar Collatz, in 1937
Why:

He was a German mathematician and the conjecture carries his name.

Q8 Which of these describes the Collatz conjecture correctly today? advanced
  • A It has been proved true for every whole number
  • B It has been proved false by a counter-example
  • C It is unproved, and no exception has ever been found
  • D It was withdrawn once computers began testing it
Show answer
Answer: It is unproved, and no exception has ever been found
Why:

Enormous searches agree with it, and agreement is not proof.

Q9 Why is a computer search unable to settle a claim about all whole numbers? advanced
  • A Because computers make arithmetic mistakes too often to be relied on
  • B Because the whole numbers never run out, so infinitely many stay untested
  • C Because a search can only test the even numbers and skips every odd one
  • D Because the results of a search are always kept secret by the people running it
Show answer
Answer: Because the whole numbers never run out, so infinitely many stay untested
Why:

However far a search reaches, endlessly many starts lie beyond it.

Q10 An estimate is best described as ____. beginner
  • A a failed attempt at an exact answer, made when the exact one proves too hard
  • B a rough answer that is close enough for the question
  • C an answer that has been rounded by accident
  • D a guess made without any working at all
Show answer
Answer: a rough answer that is close enough for the question
Why:

Being rough is the point, not a weakness.

Q11 Three sections of a class hold 38, 41 and 36 children. Which estimate is most sensible for the whole class? beginner
  • A About 90
  • B About 120
  • C About 200
  • D About 400
Show answer
Answer: About 120
Why:

They come to 115, which rounds comfortably to 120.

Q12 The school has five classes of a similar size. About how many children does it hold? intermediate
  • A About 250
  • B About 400
  • C About 600
  • D About 1,200
Show answer
Answer: About 600
Why:

Five lots of about 120 come to about 600.

Q13 Why is it better to carry 120 than 115 into the next stage of an estimate? intermediate
  • A Because 115 is the wrong total for the three sections
  • B Because a total that ends in a five may not be multiplied by a whole number
  • C Because a round figure keeps the working easy and stays honest about accuracy
  • D Because estimates must always be rounded upwards
Show answer
Answer: Because a round figure keeps the working easy and stays honest about accuracy
Why:

An estimate that looks exact misleads the reader.

Q14 Consider these statements about the Collatz rule. I. The rule halves an even number. II. A power of two takes the longest of all to reach 1. III. Nobody has proved that every whole number reaches 1. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are correct. II is the opposite: a power of two falls straight to 1, because halving it never produces an odd number.

Q15 Two players add 1, 2 or 3 in turn and whoever says 21 wins. Which totals are safe to hand over? intermediate
  • A 2, 6, 10, 14, 18
  • B 4, 8, 12, 16, 20
  • C 3, 6, 9, 12, 15, 18, 21
  • D 1, 5, 9, 13, 17, 21
Show answer
Answer: 1, 5, 9, 13, 17, 21
Why:

Step back from 21 in fours and these are the totals you reach.

Q16 In that game the gap between safe numbers is four because ____. intermediate
  • A the target 21 can be divided by four
  • B there are four players taking part
  • C each player is allowed to add any amount from one right up to four
  • D the largest jump is three, and one more than that is four
Show answer
Answer: the largest jump is three, and one more than that is four
Why:

Whatever your rival adds, you can make the pair of moves come to four.

Q17 Who should win the game of 21 with correct play? intermediate
  • A The first player, by opening with 1
  • B The second player, by answering every move
  • C Whichever player reaches 17 first, whoever that is
  • D Neither, because the game always ends in a draw
Show answer
Answer: The first player, by opening with 1
Why:

Twenty-one is not a multiple of four, so the opening move can claim the first safe number.

Q18 Now players add anything from 1 to 10 and the winner says 99. Who wins with correct play? advanced
  • A The first player, by opening with 1
  • B The first player, by opening with 10
  • C The second player, because 99 sits exactly on a gap of eleven
  • D It depends entirely on luck, because neither player is able to plan ahead
Show answer
Answer: The second player, because 99 sits exactly on a gap of eleven
Why:

The safe totals are the multiples of eleven, and the first player cannot reach 11 in one move.

Q19 Match each game with its winner: (i) target 21 adding up to 3, (ii) target 99 adding up to 10. advanced
  • A (i) first player and (ii) second player
  • B (i) second player and (ii) first player
  • C (i) first player and (ii) first player
  • D (i) second player and (ii) second player
Show answer
Answer: (i) first player and (ii) second player
Why:

Twenty-one is not a multiple of four, while ninety-nine is a multiple of eleven.

Q20 Players add 1, 2, 3 or 4 and the winner says 30. Which statement is true? advanced
  • A The first player wins by opening with 5
  • B The first player wins by opening with 1
  • C The game cannot be won by either player, since 30 is never landed on exactly
  • D The second player wins, since 30 is a multiple of the gap of five
Show answer
Answer: The second player wins, since 30 is a multiple of the gap of five
Why:

The gap is five, the safe totals are the multiples of five, and the opener cannot reach 5.

Important short questions (6)

State the Collatz rule and use it to write the first four numbers of the run that starts at 7.

Halve an even number, and treble an odd number before adding one. Starting at 7 the run reads 7, 22, 11, 34.

Why does the run that starts at 32 never climb?

Every number in it is a power of two. Halving one gives another power of two, so no odd number ever turns up to send it upwards.

Write a careful sentence about the state of the Collatz conjecture today.

Collatz put it forward in 1937 and it has never been proved. Huge computer searches have found no exception, but that is evidence rather than a proof.

Maryam's three sections hold 38, 41 and 36 children. Estimate the size of her school, which has five such classes.

The three sections come to 115, so a class is about 120. Five classes of that size give an estimate of about 600 children.

In the game where players add 1, 2 or 3 and the winner says 21, what should the first player say first, and why?

She should say 1. That is the lowest safe total, and from there she can answer every move to reach 5, 9, 13, 17 and 21.

Explain how to find the gap between safe numbers in any game of this kind.

Add one to the largest jump the rules allow. That gap lets you answer any move your opponent makes and still land on the next safe total.

Long answer questions (3)

Think and write: build the Collatz run that starts at 15, describe its shape, and say what it does and does not show about the conjecture.

Fifteen is odd, so it becomes 46, and 46 is even, so it becomes 23. The run climbs to 106, falls back, climbs once more and finally arrives at 1 after seventeen steps. Its shape is a series of climbs and drops rather than a smooth slide. What it shows is that this one starting number behaves as Collatz suggested. What it does not show is anything about the numbers nobody has tried. One run, or a billion runs, cannot settle a claim made about every whole number there is.

Think and write: describe how you would estimate the number of words in your mathematics textbook, and say where your estimate could go wrong.

I would count the words in three or four lines and take a typical figure, say ten. Then I would count the lines on a full page, perhaps thirty, which gives about 300 words a page. Multiplying by the number of pages gives my estimate. It could go wrong in several ways. Pages holding pictures or exercises carry far fewer words than a page of prose. My sample lines might be unusually long or short. So I would treat the answer as a rough size rather than a count, and say so clearly.

Think and write: explain the winning strategy for the game of 21, then show how changing the rules to a target of 99 with jumps up to ten moves the advantage.

In the game of 21 the largest jump is three, so safe totals are spaced four apart. Working back from 21 gives 17, 13, 9, 5 and 1. The first player says 1 and afterwards answers each move so that the pair of moves comes to four. She lands on every safe total and wins. Change the rules so that players add up to ten and the winner says 99. The gap becomes eleven and the safe totals are the multiples of eleven. The first player cannot reach 11 in a single move, so the second player takes 11 and keeps control from there.

Flashcards (15)

State the Collatz rule.
Halve an even number; treble an odd number and add one. Then repeat on the answer.
What does 15 become under the Collatz rule?
46, because 15 is odd, so it is trebled and given one more.
Write the whole Collatz run that starts at 32.
32, 16, 8, 4, 2, 1.
Why does a power of two reach 1 without climbing?
Halving a power of two gives another power of two, so no odd number ever appears.
What is remarkable about the run that starts at 27?
It climbs as high as 9,232 and takes 111 steps before it reaches 1.
Who proposed the Collatz conjecture, and when?
Lothar Collatz, a German mathematician, in 1937.
Has the Collatz conjecture been proved?
No. Nobody has proved it, and it is among the best known questions still open in the subject.
Why can a computer search never settle the Collatz conjecture?
The whole numbers never run out, so infinitely many starts stay untested however far a search goes.
What is an estimate?
A rough answer, built on purpose, that is close enough for the question being asked.
Three sections hold 38, 41 and 36 children. What is a sensible estimate for the class?
About 120, since the exact total is 115 and a round figure is easier to work with.
Why round 115 up to 120 rather than keeping the exact figure?
The next stage multiplies it, and a round number keeps that easy without pretending to be exact.
How would you estimate the breaths you take in a day?
Count them for a minute, multiply by sixty for an hour, then by twenty-four for a day.
In the game where players add 1, 2 or 3 and the winner says 21, which totals are safe?
1, 5, 9, 13, 17 and 21.
Why is the gap between safe numbers four in that game?
The largest jump is three, so you can always answer your opponent's move and move four in total.
In the version where players add up to 10 and the winner says 99, who wins with correct play?
The second player, because 99 sits exactly on the gap of eleven.

Play this topic

  • Term and meaning
  • Crack an adding game
  • Fact or myth?
  • Unscramble the word
  • Finish the sentence

Class 6 Mathematics Chapter 3 — frequently asked questions

Explain in your own words what a child's number reports in the lining-up game.

It counts how many of the people standing right beside that child are taller than the child is.

Why can the two children at the ends of a row never call out 2?

Each of them has a neighbour on one side only. Counting two taller neighbours needs a person on both sides.

Four children of heights 122, 130, 145 and 138 centimetres stand in that order. Write down what each calls out.

They call out 1, 1, 0 and 1. The 145 cm child beats both neighbours, and each of the others has exactly one taller neighbour.

Explain what a digit sum is and why 89 and 98,000 share one.

A digit sum adds the digits and ignores what each is worth. The digits of both numbers are 8 and 9, plus zeros, so both come to 17.

How many times does the digit 4 appear when the numbers 1 to 100 are written out? Show your reasoning.

Twenty times. It appears ten times in the units place and ten more times through the forties, and nothing else contributes.

Explain how to check quickly whether 7,337 is a palindrome.

Pair the outer digits and then the inner ones. Both outer digits are 7 and both inner digits are 3, so it reads the same either way.

Explain how you decide whether a clock reading is a palindrome, using 12:21 as your example.

Drop the colon, which leaves the digits 1221. Read them from the other end and they are unchanged, so the time is a palindrome.

Why does each single-digit hour on a clock contain exactly six palindromic times?

The final minute digit has to copy the hour digit. The first minute digit can only be 0, 1, 2, 3, 4 or 5, which gives six choices.

Using the digits 9, 2, 6 and 4, write the largest and the smallest four-digit numbers and give their difference.

The largest is 9642 and the smallest is 2469. Their difference is 7173.

State the Collatz rule and use it to write the first four numbers of the run that starts at 7.

Halve an even number, and treble an odd number before adding one. Starting at 7 the run reads 7, 22, 11, 34.

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