Class 6 Mathematics Chapter 5: Prime Time
- 4 topics
- 80 MCQs
- 24 short answers
- 12 long answers
- 60 flashcards
- 20 games
- ~152 min read
- English
Common Multiples and Common Factors
Two lists set side by side: the numbers that appear in both lists of multiples, and the numbers that appear in both lists of factors, with the reason one set is endless and the other is not.
What you will be able to do
- I can list the multiples and the factors of a number in order without missing any.
- I can find the common multiples of two numbers and pick out the smallest one.
- I can find every common factor of two numbers and pick out the largest one.
- I can explain why common multiples never run out while common factors always do.
Key points
A multiple of a number is that number times a counting number, so the multiples of any number carry on without end.
A number standing in both lists of multiples is a common multiple; 12, 24, 36 and 48 are common multiples of 4 and 6.
The smallest common multiple of 4 and 6 is 12, and every later one is 12 more than the one before.
A factor divides a number exactly, leaving nothing over, so no factor of a number is bigger than that number.
A number standing in both lists of factors is a common factor; 1, 2, 3 and 6 are the common factors of 18 and 30.
Since 1 divides every number exactly, any two numbers you pick already share 1 as a common factor.
A list of common factors comes to an end, while a list of common multiples does not.
Write both lists in order and ring what appears twice; guessing at the answer leaves entries out.
Full explanation
Two lamps on a stage
Devika is looking after the lights for a school play. One green lamp blinks every 4 seconds. One red lamp blinks every 6 seconds. Both are switched on together at the count of zero. Devika wants to know when the stage will flash green and red at the very same instant.
The green lamp's counts
The green lamp blinks at 4, 8, 12, 16, 20 and 24 seconds, and onwards. These counts are the multiples of 4. A multiple of 4 is what you get when 4 is multiplied by a counting number. The list carries on for ever, because there is always a next counting number.
The red lamp's counts
The red lamp blinks at 6, 12, 18, 24, 30 and 36 seconds. These counts are the multiples of 6. Notice that the red marks are more spread out than the green ones. A bigger step size gives fewer blinks in the same stretch of time.
Numbers that stand in both lists
Read the two lists side by side. The numbers 12, 24, 36 and 48 stand in both of them. A number that is a multiple of 4 and also a multiple of 6 is called a common multiple of 4 and 6. At those counts the stage flashes green and red together.
The first time they agree
Of all the common multiples, 12 is the smallest. So the two lamps flash together for the first time at 12 seconds. After that they agree again every 12 seconds. That is why 24, 36 and 48 are on the list as well.
Common multiples never run out
Could Devika name the largest common multiple of 4 and 6? She could not. Add 12 to any common multiple and you have another one. The list 12, 24, 36, 48, 60 keeps growing for as long as you keep writing. Common multiples are endless, just as multiples are.
A tray of sweets
Now for a different sort of question. Meher has 18 laddoos and 30 pedas. She wants to fill identical plates. Every plate must hold the same number of laddoos, with none left over. Every plate must also hold the same number of pedas, with none left over. How many plates can she use?
Factors, in one line
A factor of a number divides it exactly, leaving no remainder. The factors of 18 are 1, 2, 3, 6, 9 and 18. The factors of 30 are 1, 2, 3, 5, 6, 10, 15 and 30. Each list stops, because a factor is never larger than the number it divides.
Numbers that divide both
Compare the two factor lists. The numbers 1, 2, 3 and 6 stand in both. These are the common factors of 18 and 30. So Meher can use 1, 2, 3 or 6 plates. With 6 plates, each one holds 3 laddoos and 5 pedas.
The quietest factor of all
Every factor list opens with 1, because 1 divides every number exactly. So any two numbers you choose already share a common factor, and that factor is 1. A pair that shares nothing beyond 1 has a name of its own, and the next topic gives it.
The largest common factor
The biggest number on the shared list is 6. It gives Meher the most plates she can fill. Unlike common multiples, common factors do come to an end, because nothing bigger than 18 can be a factor of 18.
Multiples march out, factors fit in
Keep the two ideas apart with one question. Am I multiplying or am I dividing? The multiples of 18 are 18, 36, 54 and onwards, marching away from 18. The factors of 18 are 1, 2, 3, 6, 9 and 18, all sitting at 18 or below.
Write the list, do not guess
Guessing a common factor is slow and it misses some. Write both factor lists in order, then ring what appears twice. For common multiples, write out a few multiples of the larger number, then test each one against the smaller. Nothing is left out that way.
A check before you finish
Take every answer back to the question. For a common factor, divide both numbers by it and look for a remainder of zero. For a common multiple, divide it by both numbers in the same way. If either division leaves something over, that number does not belong on your list.
Concepts and terms
What you land on by counting in equal steps from a number. Step in fours and you land on 4, 8, 12, 16 and onwards. There is always a next step to take, so no number has a biggest multiple.
A number that shares another one out evenly, with nothing left in your hand. The factors of 20 are 1, 2, 4, 5, 10 and 20. Because sharing cannot use pieces bigger than the whole, the list stops at the number.
A number that two different step sizes both reach. Step in fours and step in sixes, and both journeys touch 12. Every common multiple of 4 and 6 is a stopping place the two journeys share.
A number that shares out two different amounts evenly at the same time. It has to divide each one with no remainder. Test it on both amounts, not on the first one alone.
Watch out!
Myth or reality
Case Study
Scenario:
Two bus routes leave the same stop. One goes every 12 minutes and the other every 18. They set off together at 6 am. A class is asked when they will next leave together. Imran says every 30 minutes, adding the two. Their teacher asks the class to list the departure times instead. The first route goes at 12, 24, 36, 48 and so on. The second goes at 18, 36, 54. They first meet again at 36 minutes. Imran sees that adding was the wrong operation. The answer is the lowest common multiple, because the buses meet where the two lists of multiples agree.
Analysis:
Adding the intervals gave 30, and the lists agree at 36. The meeting point is where both sequences land, which is what a common multiple is.
Activity:
Pick two intervals, such as 8 and 10 minutes. List the departure times of each and mark where they first meet.
Build the blinking strip
Title:
Build the blinking strip
What You Notice:
The beans land on 12, 24, 36 and 48, spaced evenly at twelve boxes apart. The first bean marks the smallest common multiple, and the even spacing shows why adding 12 to one answer always gives another.
Did you know
Stage crews really do plan flashing lights this way, choosing step sizes so that two lamps meet only rarely.
Bus timetables use the same idea: two routes leaving every 12 and every 20 minutes meet again only every 60 minutes.
Gear wheels with 8 and 9 teeth return to their starting position together only after 72 teeth have passed.
Memory tricks
Telling multiples from factors — Factors fit inside, multiples march out — A factor sits at the number or below it, because it fits into the number. A multiple sits at the number or above it, because it is the number counted again.
Hunting for a common multiple — Start with the bigger step — List the multiples of the larger number first. There are fewer of them, so there is less work. Then test each one against the smaller number.
Practice MCQs with answers (20)
- A At 10 seconds, because 4 and 6 added together give 10
- B At 12 seconds, the smallest number standing in both lists
- C At 24 seconds, the two step sizes multiplied together
- D At 6 seconds, because 6 is the larger of the two step sizes
Show answer
Why:
The green lamp reaches 12 and so does the red one, and nothing smaller does both.
- A common factor
- B common multiple
- C counting number
- D remainder
Show answer
Why:
Appearing in both lists of multiples is exactly what the name describes.
- A Adding 12 to any common multiple gives another one, so the list never ends
- B Because 4 and 6 are both even, and even numbers have no largest multiple
- C Because the two lists of multiples never actually meet at any number
- D Because a common multiple has to be smaller than 4 and 6 to begin with
Show answer
Why:
There is always a bigger one waiting, so no last one can be named.
- A Every common factor of two numbers is larger than both of the numbers
- B Two numbers can be chosen so that they share no common factor at all
- C Every pair of whole numbers has 1 as a common factor
- D A number's factors carry on for ever, just as its multiples do
Show answer
Why:
1 divides everything, so it is on every factor list and therefore on every shared list.
- A 1, 2, 3, 9, 18
- B 1, 2, 3, 6, 18
- C 2, 3, 6, 9, 18
- D 1, 2, 3, 6, 9, 18
Show answer
Why:
All six of these divide 18 exactly, and nothing else does.
- A One gives 1, 2, 4, 8 and two gives 1, 3, 5, 15
- B One gives 1, 2, 4 and two gives 1, 3, 5, 9, 15
- C One gives 1, 2, 4 and two gives 1, 3, 5, 15
- D One gives 1, 2, 4, 5 and two gives 1, 5, 15
Show answer
Why:
8 does not divide 20, and 9 does not divide 60, so neither belongs on a shared list.
- A 6 plates, each holding 3 laddoos and 5 pedas
- B 5 plates, each holding 4 laddoos and 6 pedas
- C 9 plates, each holding 2 laddoos and 4 pedas
- D 10 plates, each holding 2 laddoos and 3 pedas
Show answer
Why:
6 divides both amounts exactly; 5, 9 and 10 each fail on one of them.
- A Nothing is wrong, because 24 and 18 are both even numbers
- B Nothing is wrong, because 18 and 24 share the common factor 6
- C A factor has to be an odd number, and 24 is an even one
- D A factor cannot be larger than the number it divides
Show answer
Why:
Sharing 18 into parts cannot use a part of size 24.
- A 3
- B 18
- C 27
- D 54
Show answer
Why:
18 is the first number reached by counting in sixes and also by counting in nines.
- A Both lists are endless, so neither of them has a largest member
- B Both lists come to a stop, so each of them has a largest member
- C Common factors stop; common multiples do not
- D Common multiples stop; common factors do not
Show answer
Why:
Factors are capped by the numbers themselves, while multiples keep growing.
- A 30 fails, because dividing it by 4 leaves a remainder of 2
- B 30 works, because dividing it by 4 and by 6 leaves nothing over
- C 30 works, because 30 is bigger than 4 and 6 put together
- D 30 fails, because dividing it by 6 leaves a remainder of 4
Show answer
Why:
It passes the test for 6 but not the test for 4, and a common multiple must pass both.
- A At 22 seconds
- B At 120 seconds
- C At 24 seconds
- D At 60 seconds
Show answer
Why:
60 is the first number reached by counting in tens and also by counting in twelves.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
I and III are correct. II is not: a factor divides the number exactly, so it is never bigger than the number itself.
- A Because the larger number has more multiples below any given point
- B Because only the larger number's multiples can ever be common ones
- C Because its multiples are fewer, so there is less to test
- D Because the smaller number has no multiples worth testing at all
Show answer
Why:
A bigger step size puts fewer landing places inside the same stretch.
- A One is a common multiple, two is a common factor
- B One is a common factor, two is a common multiple
- C Both of them are common factors of their pairs
- D Both of them are common multiples of their pairs
Show answer
Why:
12 is reached by counting in fours and sixes; 6 divides both 18 and 30.
- A no number
- B only itself
- C its own largest factor
- D 1
Show answer
Why:
1 stands at the head of every factor list ever written.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
Both are true, and the reason is why the list steps in twelves: 12, 24, 36, 48.
- A 3 bunches
- B 9 bunches
- C 5 bunches
- D 15 bunches
Show answer
Why:
9 divides 45 but not 60, so it is not a common factor of the two amounts.
- A 1, 2, 3, 6 and 9
- B 1, 2, 3 and 6
- C 2, 3 and 6
- D 1, 2, 3, 5 and 6
Show answer
Why:
9 fails on 30, 5 fails on 18, and 1 must not be left out.
- A Because factors are always odd, and odd numbers run out quickly
- B Because a number has at most four factors, however large it is
- C Because the list has to stop at 10, since we count in tens
- D Because no factor can be bigger than the number itself
Show answer
Why:
There are only so many numbers up to the number itself, so the list is finite.
Important short questions (6)
A factor of 12 divides it exactly and is 12 or less. A multiple of 12 is 12 counted over again, so it is 12 or more.
They are 1, 2 and 4. The largest of the three is 4.
They are 40 and 80. Each of them divides by 5 and by 8 with nothing left over.
Because 1 divides every number exactly, it stands at the start of both factor lists, so it is always shared.
Twelve piles. Each pile then holds 2 saplings and 3 stones, and nothing is left over.
After 18 minutes, which is the smallest common multiple of 6 and 9.
Long answer questions (3)
They pull in opposite directions. A common factor divides both numbers, so it sits at or below the smaller of them. A common multiple is reached by counting up in both step sizes, so it sits at or above the larger of them. For 4 and 6, the only common factors are 1 and 2, while the common multiples begin at 12 and climb. One question asks how a number can be shared out, and the other asks when two counts agree. The lists cannot be swapped, and only one of them ever comes to an end.
I would write each factor list in full before comparing anything. For 45 I test every number from 1 upwards and keep 1, 3, 5, 9, 15 and 45. For 60 the same test keeps 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60. Then I read the two lists side by side and ring what appears in both, which gives 1, 3, 5 and 15. Last I check each one by dividing both numbers by it and looking for a remainder of zero.
Take the smallest common multiple of two numbers and keep adding it to itself. Each total is still reached by both step sizes. So each total is another common multiple, and nothing ever stops the process. Common factors are held in by a ceiling instead. A factor of a number cannot be bigger than that number. So no common factor of 18 and 30 can pass 18. Only the whole numbers up to 18 need testing, and there are few of those. The list is bound to finish.
Flashcards (15)
Play this topic
- Pair and answer
- Where does it belong?
- Fact or myth?
- Unscramble the word
- Find a common factor, in order
Prime Numbers, and Co-primes
Numbers with exactly two factors, numbers with more than two, the one number that has neither, and what it really means for a pair of numbers to be co-prime.
What you will be able to do
- I can say what a prime number is by counting its factors, and explain why 1 is not one.
- I can sort numbers up to 50 into primes and composites using a sieve.
- I can decide whether a pair of numbers is co-prime by comparing their factors.
- I can show with an example that a co-prime pair need not contain any prime number.
Key points
A prime number has exactly two different factors, which are 1 and the number itself.
A composite number has more than two factors, so it has a factor besides 1 and itself.
The number 1 has only one factor, so it is neither prime nor composite.
2 is prime, and it is the only even prime, since every larger even number also has 2 as a factor.
There are 15 primes up to 50, and a sieve finds them by striking out the multiples of each one in turn.
Two numbers are co-prime when no number except 1 divides both of them.
A co-prime pair need not hold a prime at all: 8 and 9 are both composite and still co-prime.
Two different prime numbers are always co-prime, because each one has only 1 and itself as factors.
Full explanation
Rows on the school ground
The games teacher wants her class in equal rows, with no child left standing out. On Monday twenty children turn up. On Tuesday nineteen turn up. She finds that Monday is easy and Tuesday is oddly stubborn, and she cannot see why at first.
Twenty children, three shapes
With twenty she has a choice. One row of 20. Two rows of 10. Four rows of 5. Each choice is a pair of numbers whose product is 20. So each number used is a factor of 20, and the full list is 1, 2, 4, 5, 10 and 20.
Nineteen children, one shape
With nineteen she has no choice at all. One row of 19 is the only equal arrangement. Two rows would leave a child over, and so would three, four, five and every other size she tries. The factor list of 19 holds only 1 and 19.
What the rows were telling her
The number of shapes and the number of factors go together. A number with plenty of factors offers plenty of arrangements. A number with only 1 and itself offers exactly one. So counting factors settles the question, and no rows need drawing.
Exactly two factors
A number with exactly two different factors is called a prime number. Those two are always 1 and the number itself, with nothing between. So 19 is prime, and so are 2, 3, 5, 7, 11, 13, 17, 23 and 29. Count the factors and the answer must be two.
More than two factors
A number with more than two factors is called a composite number. It has at least one factor besides 1 and itself, and that extra factor is the second arrangement. So 20 is composite, and so are 4, 6, 8, 9, 10, 12 and 14.
Where 1 stands
The number 1 has one factor only, which is 1. That is fewer than two, so 1 is not prime. It is also not more than two, so 1 is not composite. The number 1 belongs to neither group, and it is not a small prime with a low count.
The only even prime
The number 2 has factors 1 and 2 only, so 2 is prime. Every other even number has 2 in its factor list as well as 1 and itself, which makes three factors at least. So no even number above 2 can be prime, and 2 stands alone.
Sifting the numbers to 50
Write 1 to 50 in a grid. Strike out 1, which is in neither group. Ring 2 and strike out every later multiple of 2. The next number still standing is 3, so ring it and strike out its later multiples. Do the same for 5, then for 7.
What is left standing
Fifteen numbers survive with a ring: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47. Those are the primes up to 50. The 34 numbers struck out are the composites, and 1 sits apart from both.
Why the sieve works
A composite number has a factor besides 1 and itself, so it is a later multiple of some smaller number. That is exactly what gets struck out. A prime has no such smaller factor, so no strike ever reaches it and its ring survives.
Two numbers that share nothing
Now a question about pairs. Chandan has 8 red marbles and 9 green ones. He wants equal groups of each colour, using the same group size, and the size must be more than 1. He tries 2, 3 and 4 and every one of them fails.
Co-prime, stated carefully
The factors of 8 are 1, 2, 4 and 8. The factors of 9 are 1, 3 and 9. The only number on both lists is 1. Two numbers are co-prime when no number other than 1 divides both of them, so 8 and 9 are co-prime.
Co-prime does not mean both prime
Look again at 8 and 9. Neither one is prime, since each has more than two factors. They are still co-prime, because being co-prime is about what a pair shares and not about what either number is. Also 21 and 22 are co-prime, and 25 and 33.
Two different primes always are
Take 7 and 11. The factors of 7 are 1 and 7. The factors of 11 are 1 and 11. Their lists can meet only at 1, since 7 and 11 are not equal. So any two different primes are co-prime, while two composites may or may not be.
Concepts and terms
A number whose factor list holds just two entries, 1 at the start and the number itself at the end, with nothing between them. Count the factors and the answer must be two, not fewer and not more. 7, 11 and 29 are primes.
A number whose factor list runs past two entries. Somewhere between 1 and the number sits at least one more factor. That extra factor is what lets the number be split into equal groups in more than one way.
The factor list of 1 holds one entry only, because 1 is its own beginning and end. One is not two, so 1 misses the prime test. One is not more than two either, so 1 misses the composite test as well.
Two numbers whose factor lists meet only at 1. Neither number has to be prime for this to happen. It is a fact about the pair, never about one number on its own, so nothing is co-prime by itself.
Watch out!
Myth or reality
Two cogs in a village flour mill
Scenario:
Sushila's grandmother runs a small hand-cranked flour mill. Inside it two toothed wheels turn against each other. The small wheel has 8 teeth and the large one has 9. Sushila paints one tooth on each wheel red, then lines the two red teeth up and begins to crank. She watches for the red teeth to meet again. They pass each other tooth after tooth, and only after 72 teeth have gone by do the two red marks come together once more. Her science teacher tells her this is deliberate. When the tooth counts share no factor above 1, every tooth of one wheel meets every tooth of the other in turn. That spreads the wear evenly, so no single tooth is ground down first.
Analysis:
A co-prime pair of tooth counts makes every tooth meet every other tooth, which spreads wear. The shared meeting point comes only at the product of the two counts.
Activity:
Cut two card discs, one with 8 notches and one with 9, mark one notch on each, and turn them together to count how many notches pass before the marks line up.
Did you know
A sieve of this kind was worked out in Greece more than two thousand years ago and is still the quickest way to list small primes.
Primes come in pairs two apart surprisingly often: 11 and 13, 17 and 19, 29 and 31 are all such twins below 50.
Bank and internet security rests on the fact that multiplying two huge primes is easy while taking the product apart again is not.
Memory tricks
Counting the factors — One, two, many — One factor means the number is 1, which stands alone. Exactly two factors means prime. Many, meaning more than two, means composite. Every whole number above zero lands in one of the three.
What co-prime is about — Co-prime is a pair word — A number is prime on its own, but co-prime always needs two numbers. Ask what the pair shares, not what either one is.
Practice MCQs with answers (20)
- A 19 is composite, because only one arrangement is possible
- B 19 is prime, because its only factors are 1 and 19
- C 19 has three factors, one for each row shape it allows
- D 19 is neither prime nor composite, just as 1 is not
Show answer
Why:
One equal arrangement means one pair of factors, and that pair is 1 and the number.
- A composite
- B prime
- C even
- D square
Show answer
Why:
Two factors, and no more, is the whole of the test.
- A It has only one factor, and a prime needs exactly two different ones
- B It is too small to be useful, so it is left out of the list by habit
- C It is composite instead, since every number can be divided by it
- D It is odd, and the primes above 2 are the even numbers only
Show answer
Why:
The factor list of 1 holds a single entry, so it fails a test that asks for two.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
I and III are correct. II is not: 1 has only one factor, so it is neither prime nor composite.
- A exactly one
- B exactly two
- C fewer than two
- D more than two
Show answer
Why:
There is always at least one factor besides 1 and the number itself.
- A 29 is composite and 49 is prime
- B Both of them are prime numbers
- C 29 is prime and 49 is composite
- D Both of them are composite numbers
Show answer
Why:
Nothing but 1 and 29 divides 29, while 7 divides 49.
- A The 15 prime numbers up to 50
- B The 34 composite numbers up to 50
- C Every odd number up to 50
- D Only the four numbers 2, 3, 5 and 7
Show answer
Why:
Fifteen numbers survive every round of striking out, and those are the primes.
- A Because 29 is larger than 26, and the sieve works from the top down
- B Because 26 has two digits, and only such numbers are ever struck out
- C Because 29 is a multiple of 2 that the sieve happens to miss
- D Because 2 divides 26 exactly but leaves a remainder in 29
Show answer
Why:
Only exact multiples are struck out, and 29 is not one.
- A the smallest prime number of all
- B neither a prime nor a composite
- C the smallest composite number
- D both prime and composite at once
Show answer
Why:
One factor is too few for prime and too few for composite.
- A They are co-prime, and both of them are prime numbers
- B They are not co-prime, because neither of them is prime
- C They are co-prime, although neither of them is prime
- D They are not co-prime, because they sit next to each other
Show answer
Why:
Their factor lists meet at 1 only, and each number has more than two factors.
- A The only number dividing both of them is 1
- B Both of them are prime, with two factors each
- C Neither of them has a factor other than itself
- D They have no factors at all apart from themselves
Show answer
Why:
Co-prime is a statement about the shared part of the two factor lists.
- A Yes, with sets of 5, since 5 divides both amounts
- B Yes, with sets of 11, since 11 divides both amounts
- C Yes, with sets of 3, since 3 divides both amounts
- D No, because 25 and 33 share only the factor 1
Show answer
Why:
5 misses 33, 11 misses 25 and 3 misses 25, and nothing above 1 divides both.
- A 1, 2, 3, 5, 7
- B 2, 3, 5, 7, 11
- C 2, 3, 4, 5, 7
- D 3, 5, 7, 11, 13
Show answer
Why:
1 is not prime, 4 is composite, and the list has to begin at 2.
- A Because both of them are even, and even numbers never can be
- B Because 18 is a multiple of 12, so one of them divides the other
- C Because 2, 3 and 6 each divide both of them
- D Because neither 12 nor 18 is itself a prime number
Show answer
Why:
A single shared factor above 1 is enough to spoil it, and here there are three.
- A One is co-prime and two is not
- B One is not co-prime and two is
- C Both of the pairs are co-prime
- D Neither of the pairs is co-prime
Show answer
Why:
14 and 25 meet at 1 only, while 13 divides both 26 and 39.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
Both are true, and the reason settles it. An even number above 2 has 1, 2 and itself at the very least, so three factors.
- A If two numbers are co-prime, at least one of them must be prime
- B Two numbers can be co-prime with neither of them prime
- C Two different prime numbers are never co-prime
- D Every composite number is co-prime with every other one
Show answer
Why:
8 and 9 settle it: composite, composite, and co-prime all the same.
- A It works with groups of 2 tokens, since both amounts are even
- B It works with groups of 4 tokens, since 4 divides each amount
- C It cannot be done, since 16 and 27 share only the factor 1
- D It works with groups of 8 tokens, since 8 divides each amount
Show answer
Why:
27 is odd, and neither 4 nor 8 divides it, so no group size above 1 fits both.
- A the number itself only
- B every number below it
- C 1 only
- D 1 and the number itself
Show answer
Why:
There are two of them, one at each end of the list.
- A Because every prime is odd, and odd numbers can share nothing
- B Because two primes multiplied together always give a prime
- C Because a prime has no factors at all, so there is nothing to share
- D Because each has only 1 and itself, and their selves differ
Show answer
Why:
The two lists can overlap only at 1 once the numbers are unequal.
Important short questions (6)
Count its factors and you must find exactly two different ones, namely 1 and the number itself. So 23 is prime.
Its factor list holds one entry only. That is fewer than the two a prime needs, and fewer than the three or more a composite needs.
Such a number has 2 as a factor as well as 1 and itself. Three factors is more than two, so it is composite.
The factors of 8 are 1, 2, 4 and 8, and the factors of 9 are 1, 3 and 9, so only 1 is shared. It surprises people because neither number is prime.
They are not. The number 7 divides 35 and also divides 49, so the pair shares a factor above 1.
There are fifteen of them, and the largest is 47.
Long answer questions (3)
First I would hand him 8 and 9. The factors of 8 are 1, 2, 4 and 8, and the factors of 9 are 1, 3 and 9, so the pair shares 1 alone and is co-prime. Yet each number has more than two factors, so neither is prime. Second I would hand him 12 and 18. Both are composite, like his first pair, but 2, 3 and 6 divide both, so this pair is not co-prime. So being composite neither stops a pair nor guarantees it. The word describes what two numbers share, not what either number is.
I would write 1 to 50 in a grid and strike out 1, which is in neither group. Then I ring 2 and strike out every later multiple of 2. The lowest number still standing is 3, so I ring that and strike out its later multiples, and I repeat the step for 5 and for 7. Fifteen rings remain. Nothing struck out could be prime, because each strike marks a later multiple of some smaller number, which means that smaller number is a third factor of it. A prime has no such extra factor.
Two is the one prime that is even, and that makes it look like an exception. It is not one. The test asks for exactly two different factors, and the factors of 2 are 1 and 2, so it passes plainly. What is special is the effect it has on the others. Every even number above it picks up 2 as an extra factor and becomes composite. So the definition is doing its job in every case, and the oddness of 2 is a result of that rule rather than a hole in it.
Flashcards (15)
Play this topic
- Prime, composite, or neither
- Fact or myth?
- Number and verdict
- True or false?
- Unscramble the word
Prime Factorisation
Breaking a number down until only primes are left, finding that every route ends at the same primes, and putting that single answer to work on co-primes and on division.
What you will be able to do
- I can break a composite number down until only prime factors are left.
- I can show that different starting splits of one number end at the same primes.
- I can use prime factorisations to decide whether two numbers are co-prime.
- I can use prime factorisations to decide whether one number divides another.
Key points
The prime factorisation of a number is that number written as a product of prime numbers.
Break a composite factor into two factors, then keep breaking, and stop only when every entry is prime.
A number greater than 1 has exactly one prime factorisation, apart from the order in which the primes are written.
Different starting splits of 90 all finish at 2, 3, 3 and 5, because order of multiplication does not change a product.
We usually write the primes in increasing order, so 90 is written as 2 x 3 x 3 x 5.
A prime number's own factorisation is just itself, and the number 1 has no prime factorisation.
Two numbers are co-prime when no prime appears in both factorisations, as with 44 and 105.
One number divides another only if the whole of its factorisation, copies included, sits inside the other's.
Full explanation
Farhan's chalk tree
Farhan is at the blackboard with the number 90. His teacher asks him to keep splitting it until he cannot split any more. He writes 90 at the top, draws two lines down from it, and writes 9 and 10 underneath. His classmate Neha would have started differently, and that turns out to matter less than either of them expects.
Start wherever you like
Farhan chose 9 and 10 because he spotted them first. He could have chosen 6 and 15, or 2 and 45. Any split into two factors is a fair start. The rule is only that the two numbers you write must multiply back to the number above them.
Split it or ring it
Now look at each new number. Is it composite? Then split it in turn. Is it prime? Then ring it and leave it alone. Farhan splits 9 into 3 and 3, and both of those are prime, so both get rings. He splits 10 into 2 and 5, and rings them too.
Reading the leaves
Four ringed numbers sit at the bottom of Farhan's tree: 3, 3, 2 and 5. Multiplying them gives 2 x 3 x 3 x 5 = 90, which is the number he started with. Writing a number as a product of primes like this is called its prime factorisation.
Neha takes another route
Neha starts 90 as 6 and 15 instead. She splits 6 into 2 and 3, and 15 into 3 and 5. Her leaves are 2, 3, 3 and 5. A third pupil starts 90 as 2 and 45, splits 45 into 5 and 9, then 9 into 3 and 3. The leaves are 2, 5, 3 and 3.
The same primes every time
Three different starts, and the same four primes at the end. Only the order on the page changed. This is the remarkable thing about prime factorisation: a number greater than 1 has exactly one, apart from the order in which you happen to write the primes.
Why the order is free
Multiplication may be carried out in any order without changing the answer. So 3 x 5 x 3 x 2 and 2 x 3 x 3 x 5 come to the same total. That is why three routes down the tree cannot disagree about what is at the bottom.
Writing it tidily
Since the order is ours to choose, we choose the tidiest: smallest prime first. So 90 is written 2 x 3 x 3 x 5, and 156 is written 2 x 2 x 3 x 13. Anyone comparing two factorisations then finds matching primes in the same place.
Prime factors, and the factorisation
These two phrases are not the same. The prime factorisation of 98 is 2 x 7 x 7. Its prime factors are just 2 and 7, because that list names the different primes once each. When a prime repeats, the factorisation is longer than the list of prime factors.
Where 1 and the primes stand
What line do you get for a prime such as 13? It is 13 itself, since there is nothing to break. And 1 has no prime factorisation at all, because no prime divides 1. That is one more reason 1 is kept out of the primes.
Building from two pieces
There is a shortcut when you already know the parts. Take 132 as 12 x 11. Now 12 is 2 x 2 x 3, and 11 is prime. Put the pieces together and 132 = 2 x 2 x 3 x 11. You need not go back to the top of the tree.
Multiply back, every time
Always finish by multiplying your primes together. For 120 the tree gives 2 x 2 x 2 x 3 x 5, and multiplying that returns 120. If the product is not the number you started with, a split went wrong somewhere and the line is worth checking.
Testing a pair for co-primes
Here is the first real use. Write 44 = 2 x 2 x 11 and 105 = 3 x 5 x 7. Not one prime turns up in both lines, so nothing above 1 can divide both numbers, and the pair is co-prime. Now try 52 = 2 x 2 x 13 and 91 = 7 x 13. The prime 13 appears in both, so this pair is not.
Testing whether one divides another
The second use is division. Is 210 a multiple of 15? Write 210 = 2 x 3 x 5 x 7 and 15 = 3 x 5. Both primes of 15 sit inside 210's line, and the primes left over are 2 and 7. So 210 = 15 x 14, and the answer is yes.
Counting the copies matters
One warning. Is 180 a multiple of 24? Write 180 = 2 x 2 x 3 x 3 x 5 and 24 = 2 x 2 x 2 x 3. Both lines use only 2s, 3s and a 5, so the primes look shared. But 24 needs three 2s and 180 has only two, so 24 does not divide 180.
Concepts and terms
A number rewritten as primes multiplied together, with nothing composite left in the line. For 132 it is 2 x 2 x 3 x 11. The line is finished when no entry can be broken up any further, and multiplying it back returns the number you began with.
A drawing that records the breaking down. The number sits at the top and splits into two factors. Any composite branch splits again, while a prime branch stops and gets ringed. The ringed leaves, read together, are the factorisation.
You may split a number wherever you like. The primes you finish with are the same every time, and only their order can differ. That is why the prime factorisation of a number can be called the prime factorisation, in the singular.
One of the different primes appearing in the factorisation. The prime factors of 98 are 2 and 7, even though 7 is written twice. So the list of prime factors is shorter than the factorisation whenever a prime repeats.
Watch out!
Myth or reality
Case Study
Scenario:
A class wants to tile a rectangular board 24 centimetres by 36 with identical square tiles and no cutting. Nita tries 5 centimetre tiles and they do not fit either side. Their teacher asks the class which sizes could possibly work. A tile must divide both 24 and 36 exactly. The children list the common factors: 1, 2, 3, 4, 6 and 12. The largest is 12, which gives two tiles along one side and three along the other. Nita sees why 5 failed. It divides neither number, and a tile that does not divide a side will always leave a gap.
Analysis:
Five could not work for a reason, not by bad luck. A tile size has to divide both sides, which is what a common factor is.
Activity:
Choose a rectangle with whole-number sides. List the square tiles that would fit it exactly and name the largest.
A tree from a paper slip
Title:
A tree from a paper slip
Safety:
Take care with the scissors and cut away from your fingers.
What You Notice:
Both trees finish with three 2s, one 3 and one 5, however different the branches looked on the way down. Multiplying the ringed numbers together returns 120 each time, which is the check that the tree was drawn correctly.
Did you know
Primes are treated as the building blocks of whole numbers, because every number above 1 is a product of them and of nothing else.
A prime factorisation is one of the few answers in mathematics that is exactly the same whichever route you take to reach it.
Splitting a very large number into its primes is so slow, even for computers, that online payments are guarded by that slowness.
Memory tricks
Knowing when to stop breaking down — Split it or ring it — Look at each number on your tree. If it is composite, split it into two factors. If it is prime, ring it and leave it alone. You are finished when every branch end carries a ring.
Testing whether one number divides another — Count the copies — It is not enough for the same primes to turn up. Each prime must appear at least as many times in the larger factorisation as it does in the smaller one.
Practice MCQs with answers (20)
- A 2, 3, 5 and 9
- B 3, 3, 10 and 2
- C 2, 3, 3 and 5
- D 9, 10, 3 and 5
Show answer
Why:
Only the ringed prime leaves count, and 9 and 10 were both split further.
- A 2 x 49
- B 2 x 7 x 7
- C 7 x 14
- D 2 x 2 x 7
Show answer
Why:
49 and 14 are composite, and two 2s with a 7 would not come to 98.
- A Because a number has only one prime factorisation, apart from the order
- B Because 6 and 15 add up to the same total as 9 and 10 do together
- C Because both routes happen to use the number 3 at their very first step
- D Because 90 is an even number, and even numbers have only one route down
Show answer
Why:
The primes at the bottom are fixed by the number, not by the route taken.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
I and III are correct. II is not: apart from the order the primes are written in, there is only one factorisation.
- A common factor
- B smallest multiple
- C remainder
- D prime factorisation
Show answer
Why:
The name says what the line is made of.
- A One is 2 x 2 x 3 x 11 and two is 5 x 7 x 7
- B One is 2 x 3 x 22 and two is 5 x 5 x 7
- C One is 2 x 2 x 3 x 11 and two is 5 x 5 x 7
- D One is 4 x 3 x 11 and two is 25 x 7
Show answer
Why:
Two fives and a seven make 175, and 22, 4 and 25 are all composite.
- A They hold the same five primes, perhaps in a different order
- B They hold different primes, since the two starts were different
- C One row will be longer than the other by exactly two entries
- D Only the tree that begins with a prime reaches the primes at all
Show answer
Why:
One number has one prime factorisation, whichever split you begin with.
- A Nothing is wrong, since 3 and 15 multiply to give 45
- B The two factors should have been written the other way round
- C She should have used 5 and 9 instead, since those are smaller
- D 15 is not prime, so the breaking down has stopped too early
Show answer
Why:
15 splits into 3 and 5, so the finished line is 3 x 3 x 5.
- A three
- B four
- C two
- D six
Show answer
Why:
Halving 144 four times reaches 9, which then gives two 3s.
- A They share the prime factor 5, so they are not co-prime
- B They share the prime factor 3, so they are not co-prime
- C They share no prime factor, so they are co-prime
- D They share the prime factor 11, so they are not co-prime
Show answer
Why:
The lines read 2 x 2 x 11 and 3 x 5 x 7, and nothing is common to both.
- A If no prime appears in both factorisations, the pair is co-prime
- B If the two factorisations are the same length, the pair is co-prime
- C If both of the numbers are composite, the pair cannot be co-prime
- D If one factorisation is longer, the shorter number divides the other
Show answer
Why:
Any shared factor above 1 would have to be built from a shared prime.
- A It works, because every prime of 24 appears somewhere in 180
- B It works, because 180 is larger than 24 by a good margin
- C It fails, because 5 appears in 180 but not in 24 at all
- D It fails, because 24 needs three 2s and 180 supplies only two
Show answer
Why:
Sharing the primes is not enough; the copies of each prime must be there too.
- A 2 x 125
- B 2 x 5 x 5 x 5
- C 5 x 50
- D 2 x 5 x 25
Show answer
Why:
125, 50 and 25 are all composite, so those lines are unfinished.
- A Because both of the strings contain exactly four numbers
- B Because addition may be done in any order without changing a total
- C Because multiplication may be done in any order
- D Because 90 is a multiple of 10, and such numbers are flexible
Show answer
Why:
Rearranging factors leaves the product where it was, so the two lines agree.
- A One uses three different primes, two uses two
- B One uses two different primes, two uses three
- C Both of them use three different primes
- D Both of them use four different primes
Show answer
Why:
The lines are 2 x 2 x 3 x 13 and 2 x 2 x 2 x 2 x 3 x 3, so it is three primes against two.
- A no
- B at least two kinds of
- C a slightly different
- D exactly one
Show answer
Why:
Every route down a factor tree finishes at the same primes.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
Both are true, and the reason is why the answer is unique: 9 x 10 gives 3 x 3 x 2 x 5 and 2 x 45 gives 2 x 3 x 3 x 5.
- A It fails, because 210 carries the extra primes 2 and 7
- B It works, and he will need 14 boxes
- C It fails, because 15 is odd while 210 is an even number
- D It works, and he will need 12 boxes
Show answer
Why:
Both primes of 15 sit inside, and the leftover primes 2 and 7 give the box count.
- A 2, 7 and 49
- B 2 and 7
- C 7 and 14
- D 2, 4 and 7
Show answer
Why:
Its line is 2 x 7 x 7, and the prime factors name each different prime once.
- A They are co-prime, since no prime is shared between them
- B They are co-prime, since 52 is even while 91 is odd
- C They are not co-prime, since both of them are composite
- D They are not co-prime, since 13 divides both of them
Show answer
Why:
The lines read 2 x 2 x 13 and 7 x 13, so 13 is shared.
Important short questions (6)
It is 2 x 2 x 3 x 11. I would multiply those four primes together and look for 132 as the answer.
Because 15 is composite, so the line is unfinished. Splitting 15 into 3 and 5 gives 3 x 3 x 5.
The factorisation is 2 x 7 x 7, with the 7 written twice. The prime factors are 2 and 7, since that list names each different prime once.
The lines read 2 x 2 x 11 and 3 x 5 x 7. No prime stands in both, so nothing above 1 divides both numbers.
No prime number divides 1, so there is nothing that could be multiplied together to make it.
They are not co-prime. Both lines hold a 3 and a 5, so 3, 5 and 15 all divide both numbers.
Long answer questions (3)
Neither of them is wrong. A tree may be started at any split, so one may begin with 2 and 60 and the other with 8 and 15. What is fixed is where the splitting has to stop, and that is when every branch end is prime. Both of them will finish with three 2s, one 3 and one 5, because 120 = 2 x 2 x 2 x 3 x 5. Only the left to right order on the page will differ, and order never changes a product. So the two trees are two routes to one answer, and multiplying back to 120 proves each of them.
First I would factorise both numbers, giving 210 = 2 x 3 x 5 x 7 and 15 = 3 x 5. Then I would look for every prime of the smaller line inside the larger one. The 3 is there and so is the 5, with a 2 and a 7 left over. Since multiplication can be reordered, 210 can be written as 3 x 5 multiplied by 2 x 7, which is 15 x 14. So 210 is divisible by 15. The method works because any divisor has to be built out of the primes the larger number already holds.
I would write both lines out. Here 180 = 2 x 2 x 3 x 3 x 5 and 24 = 2 x 2 x 2 x 3. The primes 2 and 3 do appear in both, which is what he noticed. But 24 asks for three 2s and 180 holds only two of them, so the whole of 24 will not fit inside 180. Dividing shows the same thing, since 180 shared into 24s leaves 12 over. The rule is about copies, not about names: each prime must appear at least as often in the larger line.
Flashcards (15)
Play this topic
- Number and its primes
- Build a factor tree in order
- Fact or myth?
- Finished or not finished?
- Unscramble the word
Divisibility Tests, and Fun with Numbers
Quick tests that find factors of a large number by eye: the last digit for 10, 5 and 2, the last two for 4 and the last three for 8, then two puzzles that put the whole chapter to work.
What you will be able to do
- I can test a large number for divisibility by 10, 5 and 2 from its last digit.
- I can test for divisibility by 4 using the last two digits and by 8 using the last three.
- I can explain why the last digit alone settles 10, 5 and 2 but not 4 or 8.
- I can say what makes each number in a group special, and solve a small grid of primes.
Key points
A number is a multiple of 10 exactly when its last digit is 0, so 4,730 passes and 4,735 does not.
A number is a multiple of 5 exactly when its last digit is 0 or 5.
A number is a multiple of 2 exactly when its last digit is 0, 2, 4, 6 or 8.
The last digit cannot settle 4: both 26 and 36 end in 6, yet only 36 is a multiple of 4.
A number is a multiple of 4 exactly when the number made by its last two digits is, because 100 = 4 x 25.
A number is a multiple of 8 exactly when the number made by its last three digits is, because 1000 = 8 x 125.
Quick tests for 3, 6, 7 and 9 are not taken up here; the book leaves those methods for a later class.
In a group of numbers, every member can usually be called special for a reason of its own.
Full explanation
A long number on the board
Ismail's teacher writes 4,730 on the board and asks which of the numbers from 2 to 10 divide it. Ismail reaches for long division and starts on the first one. His teacher stops him. For several of these, she says, the answer is already on the board, if he knows where to look.
Dividing by 10, by eye
List the multiples of 10: 10, 20, 30, 40 and onwards. Every one of them ends in 0, and nothing else does. So a number is a multiple of 10 exactly when its last digit is 0. Ismail's number ends in 0, so 10 divides 4,730, giving 473.
Dividing by 5
Now list the multiples of 5: 5, 10, 15, 20, 25 and onwards. The last digits go 5, 0, 5, 0 for ever. So a number is a multiple of 5 exactly when it ends in 0 or in 5. That makes 4,730 and 4,735 both multiples of 5, while 4,736 is not.
Dividing by 2
The multiples of 2 run 2, 4, 6, 8, 10, 12 and onwards, and their last digits repeat 2, 4, 6, 8, 0. So a number is a multiple of 2 exactly when it ends in 0, 2, 4, 6 or 8. Here 4,730 passes and 4,735 fails.
Why one digit is enough for those three
Think about what a ten is worth. Ten is a multiple of 10, of 5 and of 2. So every ten, every hundred and every thousand inside a number is already divisible by all three. Only the units digit is left to spoil things, which is why reading it settles the question.
The last digit fails for 4
Try the same trick on 4 and it breaks. Look at 26 and 36. Both end in 6, but 36 is a multiple of 4 and 26 is not. Look at 14 and 24, or 18 and 28. In each pair the last digits agree and the answers differ, so one digit cannot be enough.
Two digits settle 4
The reason is that a single ten is not a multiple of 4, but a hundred is, since 100 = 4 x 25. So hundreds and thousands can never spoil a test by 4, and only the tens and units can. Read the number made by the last two digits and test that instead.
Testing 3,916 for 4
The last two digits of 3,916 make 16, and 16 is a multiple of 4. So 3,916 is a multiple of 4, and dividing gives 979. Now try 3,918. Its last two digits make 18, which leaves 2 over when divided by 4, so 3,918 is not a multiple of 4.
Three digits settle 8
For 8 the same argument shifts one place to the left. A hundred is not a multiple of 8, but a thousand is, since 1000 = 8 x 125. So thousands and everything above them are safe, and the last three digits carry the whole test.
Testing 7,432 for 8
The last three digits of 7,432 make 432. Dividing 432 by 8 gives 54 exactly, so 7,432 is a multiple of 8, and the full division gives 929. Compare 7,428. Its last three digits make 428, which leaves 4 over, so 8 does not divide it.
Passing one test and failing another
These tests are linked, but not equal. Any multiple of 8 is also a multiple of 4 and of 2, because 8 already holds them. The other way round can fail. The number 3,916 passes the test by 4, yet 916 leaves 4 over when divided by 8, so it fails there.
What is not here
Only 10, 5, 2, 4 and 8 have been tested this way. There are short tests for 3, 6, 7 and 9 as well, and the book keeps those for a later class. Until then, those factors are found by dividing, and no guess about their last digits will do.
Which number looks special?
Now a puzzle to finish with. Four numbers sit in a box: 7, 18, 25 and 32. Which one looks special to you? Different answers are all correct here, because each of the four has something that none of the others has.
Four numbers, four reasons
Amrita picks 7, the only prime and the only single-digit number. Joseph picks 18, the only multiple of 3. Lata picks 25, the only multiple of 5 and the only square. Faiz picks 32, the only multiple of 4. Nobody is wrong, and comparing reasons teaches more than any single answer.
A grid of primes
Here is the last puzzle. Fill a two by two grid with primes so that each row multiplies to the number beside it and each column to the number beneath it. The rows must give 10 and 21. The left column must give 6 and the right column 35. The answer is 2 and 5 on top, with 3 and 7 below.
Concepts and terms
A short rule that tells you whether one number divides another without carrying out the division. It saves the long work on big numbers. Each rule here reads only the digits at the right-hand end, and the rest of the number may be ignored.
Ten is a multiple of 10, of 5 and of 2, so every ten, hundred and thousand in a number is already divisible by each of those three. Only whatever is left over at the units place can spoil it, so that one digit settles the matter.
A single ten is not a multiple of 4, but a hundred is, since 100 = 4 x 25. So only the tens and units can spoil a test by 4. For 8 the first safe place value is a thousand, since 1000 = 8 x 125, so three digits are read.
In a small group of numbers, a member is special when it has some property none of the others has. It may be the only prime, or the only multiple of 5, or the only square. Usually every member of the group is special in some way.
Watch out!
Myth or reality
Packing candies for a school kitchen
Scenario:
A women's co-operative in a small town makes amla candies and supplies them to a school kitchen. This month they have made 5,624 candies. The kitchen asks for them in packets of 8, with no candy left loose, because each child is to receive one packet. The youngest member of the co-operative starts a long division on a slate. Her aunt stops her and points at the last three digits instead. Dividing 624 by 8 gives 78 exactly, so the whole batch will pack with nothing over. The aunt explains that a thousand candies always split into eights, so the thousands in the count can be ignored altogether and only 624 needs testing.
Analysis:
A divisibility test turns a long division into a glance, because a thousand is a multiple of 8 and so cannot affect the answer. The test is a real time-saver in everyday work.
Activity:
Count the pencils or beans in a jar, write the total down, and use the tests for 2, 4, 5, 8 and 10 to list which group sizes would share them out with nothing left over.
Did you know
Shopkeepers and clerks used these tests long before calculators, to check a bill's total without dividing it out.
Every test here reads the digits from the right, which is why the huge left-hand part of a number can simply be ignored.
The tests for 3, 6, 7 and 9 exist too, and the book saves them for a later class rather than leaving them out of mathematics.
Memory tricks
How many digits each test reads — One, two, three: ten, four, eight — One digit for 10, 5 and 2. Two digits for 4. Three digits for 8. The harder the number is to divide by, the further left you have to look.
Passing 8 and passing 4 — Eight carries four with it — Any multiple of 8 is also a multiple of 4 and of 2, because 8 itself holds them. A multiple of 4 need not be a multiple of 8, though.
Practice MCQs with answers (20)
- A Only 2 and 5
- B All three of them
- C Only 5 and 10
- D Only 2
Show answer
Why:
A last digit of 0 passes the test for 10, for 5 and for 2 at once.
- A even
- B 0 only
- C 0 or 5
- D 5 only
Show answer
Why:
The last digits of the multiples of 5 repeat 5 and 0 for ever.
- A Because 26 and 36 end alike, yet only 36 is a multiple of 4
- B Because 4 is an even number, and even tests need even digits
- C Because the last digit of a multiple of 4 is always a 4 or an 8
- D Because no test for 4 exists, so long division must be used
Show answer
Why:
A single counter-example is enough to sink a one-digit rule for 4.
- A I and II only
- B II and III only
- C I and III only
- D I, II and III
Show answer
Why:
I and III are correct. II is not: 26 and 36 both end in 6, yet only 36 is a multiple of 4.
- A one
- B two
- C four
- D three
Show answer
Why:
A thousand is the first place value that 8 divides, so three digits are read.
- A One passes and two passes
- B One fails and two passes
- C One passes and two fails
- D One fails and two fails
Show answer
Why:
16 divides by 4 exactly, while 428 leaves 4 over when divided by 8.
- A 432 divides by 8 exactly, so 7,432 does too
- B 432 leaves 4 over, so 7,432 is not a multiple of 8
- C 432 divides by 8, but 7,432 still has to be divided in full
- D 432 is even, which already proves 7,432 is a multiple of 8
Show answer
Why:
The thousands cannot affect a test by 8, so the last three digits decide it.
- A Because 4 has two factors, one for each digit examined
- B Because every two-digit number happens to divide by 4
- C Because a number's tens digit is always double its units digit
- D Because 100 is a multiple of 4, so hundreds never upset the test
Show answer
Why:
Every hundred and every thousand is already a multiple of 4.
- A two
- B three
- C one
- D four
Show answer
Why:
Thousands are safe, so only hundreds, tens and units are left to check.
- A It is a multiple of 4, since 50 is an even number
- B It is a multiple of 8, since 350 is an even number
- C It is a multiple of 2, 5 and 10, but not of 4
- D It is a multiple of none of 2, 5 and 10
Show answer
Why:
Its last digit is 0, but its last two digits make 50, which leaves 2 over on division by 4.
- A It is a multiple of 2 and of 4 as well
- B It is a multiple of 5 as well, since 8 and 5 are close
- C It is a multiple of 10, since 8 is an even number
- D Nothing else can be said until each test is done separately
Show answer
Why:
8 already holds 4 and 2 inside it, so its multiples hold them too.
- A 7
- B 18
- C 25
- D 32
Show answer
Why:
3 divides 18, 5 divides 25 and 2 divides 32, while nothing but 1 and 7 divides 7.
- A 5
- B 0
- C an even digit
- D 0 or 5
Show answer
Why:
Every multiple of 10 ends in 0, and no other number does.
- A Because it is the only number in the box below 20
- B Because it is the only even number in the whole box
- C Because it is the only multiple of 5 in the box
- D Because it is the only number in the box that is prime
Show answer
Why:
7 and 18 both lie below 20, 25 is odd, and 7 is the prime one.
- A Top row 5 and 2; bottom row 7 and 3
- B Top row 2 and 5; bottom row 3 and 7
- C Top row 2 and 3; bottom row 5 and 7
- D Top row 3 and 7; bottom row 2 and 5
Show answer
Why:
The left column then holds 2 and 3, and the right column 5 and 7.
- A one
- B three
- C four
- D two
Show answer
Why:
Tens and units together settle it, and nothing further left matters.
- A Both true, and the reason explains the assertion
- B Both true, but the reason does not explain it
- C The assertion is true and the reason is false
- D The assertion is false and the reason is true
Show answer
Why:
Both are true, and the reason is the arithmetic: 100 = 4 x 25, so only what sits below the hundreds can leave a remainder.
- A It cannot be done, since 624 leaves 4 over when divided
- B It can be done, because 624 divides by 8 exactly
- C It cannot be done, since 5,624 is not whole thousands
- D It can be done, but only by dividing 5,624 the long way
Show answer
Why:
Dividing 624 by 8 gives 78 with nothing over, so the whole number passes.
- A 0 only
- B 0 or 5
- C any even or odd digit
- D 0, 2, 4, 6 or 8
Show answer
Why:
Those five digits are the ones the multiples of 2 end in.
- A No, because a pass by 4 always brings a pass by 8 with it
- B No, because the test by 8 reads fewer digits than the test by 4
- C No, because 4 and 8 are both even, so the two tests must agree
- D Yes; 3,916 passes the test by 4 and fails the test by 8
Show answer
Why:
Its last two digits make 16, which 4 divides, while its last three make 916, which 8 does not.
Important short questions (6)
A number is a multiple of 10 only when its last digit is 0. Since 4,735 ends in 5, it is not a multiple of 10.
The numbers 36 and 26 both end in 6. Dividing 36 by 4 comes out exactly, while dividing 26 by 4 leaves 2 over.
Its last three digits make 432, and dividing 432 by 8 gives 54 with nothing over. So 8 divides 7,432, and the answer is 929.
Because 100 = 4 x 25, every hundred and every thousand in the number is already a multiple of 4. Only the tens and units can spoil it.
The tests for 3, 6, 7 and 9 are left for a later class. Until then those factors are found by dividing.
The number 18 is the only multiple of 3 in the box. The number 32 is the only multiple of 4 in it.
Long answer questions (3)
Ten is itself a multiple of 10, of 5 and of 2. So every ten, hundred and thousand inside a number already divides by all three, and the only part that can spoil the answer is whatever sits in the units place. Reading that one digit is therefore enough. Four is different, because a single ten is not a multiple of 4. A hundred is, since 100 = 4 x 25, so hundreds and thousands are safe while tens are not. That leaves the tens and units to be checked, which is exactly the last two digits.
I would hand him 3,916. Its last two digits make 16, which 4 divides exactly, so it passes the test for 4. Its last three digits make 916, and dividing 916 by 8 leaves 4 over, so it fails the test for 8. What is true is the other way round. Every multiple of 8 is a multiple of 4 and of 2, because 8 already has them inside it. So passing the harder test brings the easier ones with it, while passing an easier test promises nothing about the harder one.
The number 7 is the only prime in the box, and the only single-digit number. The number 18 is the only multiple of 3. The number 25 is the only multiple of 5, and also the only square. The number 32 is the only multiple of 4. So each of the four can be defended, and no single answer is the right one. What the puzzle teaches is that a number has many properties at once. Picking out one of them is a choice, and hearing a classmate's choice shows you a property you had not looked for.
Flashcards (15)
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Class 6 Mathematics Chapter 5 — frequently asked questions
A factor of 12 divides it exactly and is 12 or less. A multiple of 12 is 12 counted over again, so it is 12 or more.
They are 1, 2 and 4. The largest of the three is 4.
They are 40 and 80. Each of them divides by 5 and by 8 with nothing left over.
Count its factors and you must find exactly two different ones, namely 1 and the number itself. So 23 is prime.
Its factor list holds one entry only. That is fewer than the two a prime needs, and fewer than the three or more a composite needs.
Such a number has 2 as a factor as well as 1 and itself. Three factors is more than two, so it is composite.
It is 2 x 2 x 3 x 11. I would multiply those four primes together and look for 132 as the answer.
Because 15 is composite, so the line is unfinished. Splitting 15 into 3 and 5 gives 3 x 3 x 5.
The factorisation is 2 x 7 x 7, with the 7 written twice. The prime factors are 2 and 7, since that list names each different prime once.
A number is a multiple of 10 only when its last digit is 0. Since 4,735 ends in 5, it is not a multiple of 10.
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