Class 7 Mathematics Chapter 11: Finding Common Ground

Finding Common Ground is Chapter 11 of NCERT / CBSE Class 7 Mathematics. This page has the complete chapter notes across 3 topics , 75 practice MCQs with answers and explanations , 30 important short and long questions and 51 flashcards — all written to the NCERT / CBSE syllabus and free to read.

The highest common factor, by listing and by primes

A common factor divides both numbers, and the highest of them is the HCF. Listing works for small numbers; prime factorisation works for any, taking each shared prime the smaller number of times. Two numbers with HCF 1 are coprime, and an HCF can never exceed the smaller number.

What you will be able to do

  • Find the common factors of two numbers and identify the highest.
  • Break a number into prime factors and use them to find an HCF.
  • Explain why only shared primes count, at the smaller count each.
  • Recognise coprime numbers, and that neither need be prime.
  • Apply two checks and the upper limit to any HCF found.

Key points

  • A factor divides a number exactly, leaving nothing over.

  • A common factor appears in both lists, and the highest is the HCF.

  • The HCF of 24 and 36 is 12, by listing or by primes.

  • Every number breaks into prime factors in exactly one way.

  • Only primes held by BOTH numbers can appear in the HCF.

  • Each shared prime is taken the smaller number of times.

  • The HCF of 8 and 15 is 1, so they are coprime without being prime.

  • An HCF must divide both numbers, and nothing larger must.

  • So an HCF can never exceed the smaller of the two numbers.

Full explanation

Two lengths, one shared measure

A carpenter has two planks, 24 cm and 36 cm long. She wants to cut both into equal pieces, with no wood wasted and every piece the same length.

How long can each piece be? The answer has to divide both 24 and 36 exactly.

Factors

A factor of a number divides it exactly, leaving nothing over. The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24.

The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18 and 36.

Common factors

Now compare the two lists. The numbers appearing in both are 1, 2, 3, 4, 6 and 12.

Each of those is a common factor, so each is a piece length that works for both planks.

The highest of them

The carpenter wants the longest pieces, so she wants the largest of those common factors, which is 12.

That number is called the highest common factor of 24 and 36, written HCF for short.

Listing gets slow

For small numbers, listing every factor works well enough. For large ones it is slow, and it is easy to miss one.

So there is a better method, and it uses prime numbers.

Prime factorisation

Every number can be broken down into prime factors in exactly one way. Take 18, which is 2 times 9, and 9 is 3 times 3.

So 18 is one 2 and two 3s. In the same way 45 is 3 times 15, and 15 is 3 times 5, so 45 is two 3s and one 5.

Taking what both have

Now line the two breakdowns up. The number 18 has one 2 and two 3s. The number 45 has two 3s and one 5.

The 2 appears only in 18, so it cannot help. The 5 appears only in 45. The two 3s appear in both.

So the HCF is built from the shared part

Multiply the primes that both numbers have, as many times as both have them. Here that is 3 times 3, which is 9.

So the HCF of 18 and 45 is 9. No listing was needed at all.

Take the smaller count of each prime

Notice the rule carefully. If one number has three 2s and the other has one, the HCF takes just one 2.

It takes the smaller count every time, because the HCF must divide both numbers.

Checking the method on the planks

Try it on 24 and 36 to see the methods agree. The number 24 is three 2s and one 3, and 36 is two 2s and two 3s.

Both have at least two 2s and at least one 3, so the HCF is 2 times 2 times 3, which is 12. That matches the listing.

When nothing is shared

Now take 8 and 15. The number 8 is three 2s, and 15 is one 3 and one 5.

There is no prime in both breakdowns, so there is nothing to multiply. The HCF is 1.

Coprime numbers

Two numbers whose HCF is 1 are called coprime. They share no factor except 1.

This does not mean either is prime. Both 8 and 15 have factors of their own, but none in common.

What an HCF is for

The planks were one use: the largest equal piece that divides several quantities. The same question appears in tiling, packing and sharing.

It is also what reduces a fraction to its lowest terms, by dividing top and bottom by their HCF.

Two checks worth making

First, the HCF must divide both numbers exactly. Twelve divides 24 twice and 36 three times, so that passes.

Second, nothing larger must do so. The next common factor down from 12 was 6, and no common factor above 12 appeared in either list.

Why it can never exceed the smaller number

Here is a useful limit. The HCF has to divide the smaller number, so it can never be bigger than it.

For 18 and 45 the HCF is at most 18, and it turned out to be 9. If it ever equals the smaller number, that number divides the larger one.

What carries forward

A common factor divides both numbers, and the highest of them is the HCF. Listing the factors works for small numbers, and prime factorisation works for any: take each shared prime the smaller number of times.

Two numbers with HCF 1 are coprime, which does not make either of them prime. An HCF can never exceed the smaller of the two numbers.

Concepts and terms

Common factors

Numbers that divide both of two given numbers exactly. For 24 and 36 they are 1, 2, 3, 4, 6 and 12, and the highest of them is the HCF.

Prime factorisation

Every number breaks into primes in exactly one way, which is what makes the method reliable. The number 18 is one 2 and two 3s.

Taking the shared part

Only primes held by both numbers can appear, and each is taken the smaller number of times, because the HCF must divide both.

Coprime numbers

A pair whose HCF is 1, sharing no factor except 1. It says nothing about either number being prime: 8 and 15 are coprime and neither is.

Checks and the limit

An HCF must divide both numbers and nothing larger must. Since it divides the smaller number, it can never exceed it.

Watch out

Common misconceptions

The carpenter and the apprentice

Scenario:

A carpenter has planks of 24 cm and 36 cm and wants to cut both into equal pieces with nothing wasted and the pieces as long as possible. An apprentice lists the factors of each and answers 6. For a second job, with lengths of 18 cm and 45 cm, he multiplies every prime he can see and answers 90. For a third job, with 8 cm and 15 cm, he says no cutting is possible because the two share nothing. The carpenter says two quick checks would have caught all three.

Analysis:

One answer is a common factor but not the highest, one exceeds both numbers, and one misreads an HCF of 1.

Activity:

Measure five pairs of objects, find the HCF of each pair by primes, and check every answer divides both and is the largest that does.

Cut and compare

Title:

Cut and compare

Safety:

Take the usual care with the scissors. No other hazards.

What You Notice:

The ringed lengths are 1, 2, 3, 4, 6 and 12, and cutting at 12 leaves nothing over on either strip. The primes give 9 for the second pair, and the third pair shares no prime at all, so its HCF is 1.

Did you know

Coprime says nothing about either number being prime: 8 and 15 are coprime and both have factors of their own.

Dividing the top and bottom of a fraction by their HCF is exactly what reduces it to its lowest terms.

An HCF can never exceed the smaller of its two numbers, which rules out a wrong answer at a glance.

Memory tricks

Shared primes only, at the smaller count.

An HCF never beats the smaller number.

Practice MCQs with answers (25)

Q1 One number is divided by another and the division comes out with nothing left over at all. A factor of a number is one that beginner
  • A is smaller than it
  • B is a prime number
  • C adds to it exactly
  • D divides it exactly
Show answer
Answer: divides it exactly
Why:

Leaving nothing over.

Q2 Two planks of different lengths are to be cut into equal pieces with no wood wasted from either. That needs a piece length that beginner
  • A divides one of them exactly
  • B divides both exactly
  • C is the total of the two
  • D is the difference of the two
Show answer
Answer: divides both exactly
Why:

Which is a common factor.

Q3 The factors of 24 are beginner
  • A 1, 2, 3, 4, 6, 12 and 24
  • B 1, 2, 3, 4, 6, 8, 12 and 24
  • C 2, 3, 4, 6, 8 and 12
  • D 1, 2, 4, 8 and 24
Show answer
Answer: 1, 2, 3, 4, 6, 8, 12 and 24
Why:

Each divides 24 exactly.

Q4 The factors of 36 are intermediate
  • A 1, 2, 3, 4, 6, 9, 12, 18 and 36
  • B 1, 2, 3, 4, 6, 12, 18 and 36
  • C 1, 2, 4, 9, 12 and 36
  • D 2, 3, 4, 6, 9, 12 and 18
Show answer
Answer: 1, 2, 3, 4, 6, 9, 12, 18 and 36
Why:

Each divides 36 exactly.

Q5 The common factors of 24 and 36 are intermediate
  • A 1, 2, 3, 4 and 6
  • B 2, 3, 4, 6 and 12
  • C 1, 2, 3, 4, 6 and 12
  • D 1, 2, 4, 6 and 12
Show answer
Answer: 1, 2, 3, 4, 6 and 12
Why:

The numbers in both lists.

Q6 The highest common factor of 24 and 36 is beginner
  • A 6
  • B 24
  • C 12
  • D 72
Show answer
Answer: 12
Why:

The largest in the shared list.

Q7 Listing every factor is a poor method for large numbers because it is intermediate
  • A always inaccurate
  • B slow and easy to get wrong
  • C only valid for even numbers
  • D only valid for primes
Show answer
Answer: slow and easy to get wrong
Why:

A missed factor gives a wrong answer.

Q8 A number is broken down into primes by one person and then by another, working separately. Every number breaks into primes in intermediate
  • A exactly two ways
  • B exactly one way
  • C many different ways
  • D no way at all
Show answer
Answer: exactly one way
Why:

Which is what makes the method reliable.

Q9 The number 18 is broken down until nothing but primes is left in the list. Broken into primes, 18 is intermediate
  • A two 2s and one 3
  • B one 2 and one 9
  • C one 2 and two 3s
  • D three 3s
Show answer
Answer: one 2 and two 3s
Why:

Since 18 is 2 times 9, and 9 is 3 times 3.

Q10 The number 45 is broken down until nothing but primes is left in the list. Broken into primes, 45 is intermediate
  • A two 3s and one 5
  • B one 3 and one 15
  • C three 5s
  • D one 5 and one 9
Show answer
Answer: two 3s and one 5
Why:

Since 45 is 3 times 15, and 15 is 3 times 5.

Q11 Comparing those two breakdowns, the primes in both are intermediate
  • A the single 2
  • B the single 5
  • C nothing at all
  • D the two 3s
Show answer
Answer: the two 3s
Why:

The 2 is only in 18 and the 5 only in 45.

Q12 So the HCF of 18 and 45 is intermediate
  • A 9
  • B 3
  • C 15
  • D 90
Show answer
Answer: 9
Why:

Three times three.

Q13 Why can a prime held by only one of the two numbers never help the HCF? advanced
  • A The HCF has to divide both, and that prime divides only one
  • B A prime appearing once is counted once in the breakdown
  • C Primes are only useful when they appear more than once
  • D Such a prime would make the HCF larger than both numbers
Show answer
Answer: The HCF has to divide both, and that prime divides only one
Why:

18 has a 2 and 45 has a 5. Either one would spoil the division into the other number, so neither can enter the HCF.

Q14 Where one number has three 2s and the other has one, the HCF takes advanced
  • A three 2s
  • B four 2s
  • C one 2
  • D two 2s
Show answer
Answer: one 2
Why:

The smaller count every time.

Q15 Broken into primes, the number 24 is intermediate
  • A two 2s and two 3s
  • B one 2 and one 12
  • C three 2s and one 3
  • D four 2s and one 3
Show answer
Answer: three 2s and one 3
Why:

Eight times three.

Q16 Both 24 and 36 have at least advanced
  • A three 2s and one 3
  • B two 2s and one 3
  • C two 2s and two 3s
  • D one 2 and one 3
Show answer
Answer: two 2s and one 3
Why:

Which multiply to 12.

Q17 Broken into primes, the number 8 is beginner
  • A two 2s
  • B one 2 and one 4
  • C three 2s
  • D four 2s
Show answer
Answer: three 2s
Why:

Two times two times two.

Q18 Comparing 8 with 15, the primes they share number intermediate
  • A one of them
  • B two of them
  • C three of them
  • D none at all
Show answer
Answer: none at all
Why:

Eight has 2s and 15 has a 3 and a 5.

Q19 So the HCF of 8 and 15 is beginner
  • A 1
  • B 2
  • C 3
  • D 8
Show answer
Answer: 1
Why:

There is nothing to multiply.

Q20 Two numbers are examined and the largest factor they share turns out to be 1 and nothing more. Two such numbers are described as intermediate
  • A coprime
  • B prime
  • C composite
  • D equal
Show answer
Answer: coprime
Why:

Sharing no factor except 1.

Q21 Being coprime means that the two numbers advanced
  • A are both even numbers
  • B are both prime numbers
  • C have no factors at all
  • D share no factor but 1
Show answer
Answer: share no factor but 1
Why:

Both 8 and 15 have factors of their own.

Q22 Besides cutting, an HCF is what reduces a fraction intermediate
  • A to a whole number
  • B to a decimal
  • C to a percentage
  • D to its lowest terms
Show answer
Answer: to its lowest terms
Why:

Divide top and bottom by it.

Q23 Consider these statements about an HCF. I. It must itself be a prime number. II. It can never be larger than the smaller of the two numbers. III. It must divide both numbers exactly. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: II and III only
Why:

II and III are true. The first fails: the HCF of 24 and 36 is 12, which is not prime.

Q24 An HCF can never be larger than advanced
  • A the larger of the two numbers
  • B the total of the two
  • C the smaller of the two numbers
  • D the difference of the two
Show answer
Answer: the smaller of the two numbers
Why:

Because it must divide that smaller number.

Q25 Assertion: If the HCF equals the smaller number, that number must be prime. Reason: An HCF divides both of the two numbers exactly. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: The assertion is false and the reason is true
Why:

The reason is true and the assertion is false: it means the smaller number divides the larger, as 6 does 18, and 6 is not prime.

Important short questions (7)

List the common factors of 24 and 36 and give their HCF.

The common factors are 1, 2, 3, 4, 6 and 12. The highest of them is 12, so the HCF is 12.

Why is listing every factor a poor method for large numbers?

It is slow, and it is easy to miss a factor. A single omission gives the wrong answer, so prime factorisation is used instead.

Break 18 and 45 into prime factors.

The number 18 is 2 times 9, and 9 is 3 times 3. So it is one 2 and two 3s. The number 45 is 3 times 15, and 15 is 3 times 5. So it is two 3s and one 5.

Use those breakdowns to find the HCF of 18 and 45.

The 2 appears only in 18 and the 5 only in 45, so neither helps. The two 3s appear in both, so the HCF is 3 times 3, which is 9.

Why does an HCF take the smaller count of each shared prime?

The HCF must divide both numbers. Taking a prime more times than the first number has it would give something that no longer divides that number.

Find the HCF of 8 and 15 and name what such a pair is called.

The number 8 is three 2s and 15 is one 3 and one 5, so no prime is shared and the HCF is 1. Two such numbers are called coprime.

Why can an HCF never exceed the smaller of the two numbers?

The HCF has to divide the smaller number exactly, and nothing larger than a number can divide it. So the smaller number is an upper limit.

Long answer questions (3)

Find the HCF of 24 and 36 by listing factors, then again by prime factorisation, and say why the second method is preferred.

Start by listing. The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24, and those of 36 are 1, 2, 3, 4, 6, 9, 12, 18 and 36. The numbers in both lists are 1, 2, 3, 4, 6 and 12, so the highest common factor is 12. Now use primes instead. The number 24 breaks into three 2s and one 3, and 36 breaks into two 2s and two 3s. Both have at least two 2s and at least one 3, so the HCF is 2 times 2 times 3, which is 12 again. The second method is preferred because listing is slow for large numbers and it is easy to miss a factor, which gives a wrong answer with no warning. Prime factorisation needs no list and works at any size.

Explain why an HCF takes the smaller count of each shared prime and ignores a prime that only one number has, using 18 and 45.

Break both numbers down first. The number 18 is one 2 and two 3s, and 45 is two 3s and one 5. Now take the primes one at a time. The 2 appears only in 18, so including it would give something that does not divide 45, and the HCF must divide both. The 5 appears only in 45, and is excluded for the same reason. The 3 appears in both, twice in each, so two 3s may be taken, giving an HCF of 9. The counting rule follows from the same requirement. Suppose one number had three 2s and the other only one. Taking more than one 2 would produce a number that no longer divides the second. So the smaller count is the most that can ever be used.

Find the HCF of 8 and 15, explain what coprime means, and give two checks you would apply to any HCF.

Break the two numbers down. The number 8 is three 2s, and 15 is one 3 and one 5. No prime appears in both breakdowns, so there is nothing to multiply and the HCF is 1. Two numbers with an HCF of 1 are called coprime, which means they share no factor except 1. It does not mean either of them is prime, and neither of these is: 8 and 15 both have factors of their own, just none in common. Two checks are worth applying to any HCF. The first is that it must divide both numbers exactly. The second is that nothing larger must divide both, since otherwise a bigger common factor has been missed. A useful limit is that an HCF can never exceed the smaller number.

Flashcards (17)

What is a factor of a number?
A number that divides it exactly, leaving nothing over.
What is a common factor of two numbers?
A number that appears in both lists of factors.
What is the highest common factor of 24 and 36?
Twelve.
Why is listing every factor a poor method for large numbers?
It is slow, and a single missed factor gives the wrong answer.
Break 18 into prime factors.
One 2 and two 3s.
Break 45 into prime factors.
Two 3s and one 5.
Find the HCF of 18 and 45 from those breakdowns.
Nine.
How many of each shared prime does an HCF take?
The smaller count of the two.
Break 24 and 36 into prime factors.
Three 2s and one 3, against two 2s and two 3s.
What is the HCF of 8 and 15?
One.
What are two numbers with an HCF of 1 called?
Coprime.
Does coprime mean either number is prime?
No. Both 8 and 15 have factors of their own.
Name two uses of an HCF besides cutting planks.
Tiling or packing, and reducing a fraction to lowest terms.
What is the first check on an HCF?
It must divide both numbers exactly.
What is the second check on an HCF?
Nothing larger must divide both.
Why can an HCF never exceed the smaller number?
Because it has to divide that smaller number.
What follows if an HCF equals the smaller number?
That smaller number divides the larger one.

Play this topic

  • Match each pair to its HCF
  • Does the prime belong in the HCF of 18 and 45?
  • Fact or myth
  • Order these steps for an HCF by primes
  • Match each term to its meaning

The lowest common multiple, and the larger count

A common multiple is divisible by both numbers, and the least of them is the LCM. There is no greatest, since the list never ends. By primes, take every prime at the LARGER count and keep the lone ones, the exact opposite of the HCF rule. Coprime numbers have their product as their LCM.

What you will be able to do

  • Find common multiples of two numbers and identify the least.
  • Explain why there is no greatest common multiple.
  • Find an LCM by primes, taking the larger count of each.
  • Explain why the LCM and HCF rules pull in opposite directions.
  • Use the coprime rule, and apply two checks and two limits.

Key points

  • A multiple is a number times a whole number.

  • A common multiple is divisible by both numbers, and the least is the LCM.

  • The LCM of 6 and 8 is 24, so two such bells coincide every 24 minutes.

  • The common multiples never end, so there is no greatest one.

  • An LCM takes every prime at the LARGER count and keeps the lone ones.

  • An HCF must divide both, while an LCM must be divisible by both.

  • The LCM of 12 and 18 is 36, not the 6 the HCF rule would give.

  • Coprime numbers have their product as their LCM, as 5 and 7 give 35.

  • An LCM lies between the larger number and the product of the two.

Full explanation

Two bells ringing together

A school has two bells. One rings every 6 minutes and the other every 8 minutes. They ring together at the start of the day.

When will they next ring together? The answer must be a whole number of 6 minute gaps and also a whole number of 8 minute gaps.

Multiples

A multiple of a number is what you get by multiplying it by a whole number. The multiples of 6 are 6, 12, 18, 24, 30, 36 and so on.

The multiples of 8 are 8, 16, 24, 32, 40, 48 and so on.

Common multiples

Now look for numbers in both lists. The first is 24, and 48 comes next.

Each of those is a common multiple, and each is a time when both bells ring.

The least of them

The question asked when they would NEXT ring together, so we want the smallest of the common multiples, which is 24.

That is the lowest common multiple of 6 and 8, written LCM for short. The bells ring together every 24 minutes.

There is no greatest common multiple

Notice something about the list of common multiples. After 24 comes 48, then 72, and it never stops.

So there is no highest common multiple to ask for, which is why only the lowest one is given a name.

Listing works, but not for long

As with factors, listing multiples is fine for small numbers. For large ones the lists get long before they meet.

So the prime method is better here too.

Prime factorisation again

Take 12 and 18. The number 12 is two 2s and one 3, and 18 is one 2 and two 3s.

A common multiple has to be divisible by both, so it must contain enough of every prime to cover each number.

Taking the larger count this time

For the 2s, the number 12 needs two of them and 18 needs one, so two 2s will cover both. For the 3s, 18 needs two and 12 needs one, so two 3s are needed.

Multiplying gives 2 times 2 times 3 times 3, which is 36. So the LCM of 12 and 18 is 36.

Why the larger count

The reason is the opposite of the HCF rule, and it is worth saying plainly. An HCF has to DIVIDE both numbers, so it can never take more of a prime than a number has.

An LCM has to be DIVISIBLE BY both numbers, so it must take at least as many as the greedier one needs.

And lone primes are kept

For the same reason, a prime held by only one of the numbers must still appear. Leaving it out would make the answer fail to be divisible by that number.

So an LCM keeps everything, at the larger count, while an HCF keeps only what is shared, at the smaller count.

When the numbers are coprime

Take 5 and 7, which are both prime and share nothing. The LCM must contain one 5 and one 7.

So it is 35, which is simply 5 times 7. Whenever two numbers are coprime, their LCM is their product.

Why that happens

With nothing shared, no prime is covered twice over. Every prime in either number has to appear, and none of them overlaps.

Multiplying the two numbers is then exactly what the rule asks for.

What an LCM is for

The bells were one use: when two repeating events coincide. Gears, timetables and shift patterns all raise the same question.

It is also the common bottom number used when adding fractions, and the lowest one is the LCM of the two bottoms.

Checks on an LCM

Two checks are worth making. First, both numbers must divide the answer exactly: 6 and 8 both divide 24.

Second, nothing smaller must. Twelve is divisible by 6 but not by 8, so 24 is indeed the least.

A limit worth knowing

An LCM can never be smaller than the larger of the two numbers, because it has to be a multiple of it.

It also can never exceed the product of the two. For 6 and 8 that puts the answer between 8 and 48, and 24 sits inside.

What carries forward

A common multiple is divisible by both numbers, and the least of them is the LCM. There is no greatest, which is why only the least has a name.

By primes, take every prime at the LARGER count and keep the lone ones, which is the exact opposite of the HCF rule. Coprime numbers have their product as their LCM, and any LCM lies between the larger number and the product.

Concepts and terms

Common multiples

Numbers divisible by both of two given numbers. For 6 and 8 they are 24, 48, 72 and onwards, and the least of them is the LCM.

Why no greatest exists

The list of common multiples runs on without end, so there is no highest one to name. Only the lowest is given a name.

The larger count rule

An LCM needs enough of every prime to cover both numbers, so it takes each at the larger count and keeps any prime held by only one.

Why the rules differ

An HCF must DIVIDE both numbers, capping its counts. An LCM must be DIVISIBLE BY both, so it needs at least as many as the greedier number.

Coprime pairs

Where nothing is shared, no prime is covered twice, so the LCM is simply the two numbers multiplied, as with 5 and 7 giving 35.

Watch out

Common misconceptions

The two bells and the gearwheels

Scenario:

A school has bells ringing every 6 and every 8 minutes, starting together, and the caretaker needs to know when they next coincide. A helper lists multiples and answers 48. For a pair of gearwheels with 12 and 18 teeth, the helper breaks both into primes but takes the smaller count of each, answering 6. For two cogs with 5 and 7 teeth he says no answer exists, since they share nothing. He also asks the caretaker for the greatest common multiple of 6 and 8.

Analysis:

One answer is a common multiple but not the least, one uses the HCF rule by mistake, one misreads a coprime pair, and one question has no answer.

Activity:

Time two repeating events at home, work out when they coincide by both methods, and check that both numbers divide your answer.

Ring the changes

Title:

Ring the changes

Safety:

Nothing hazardous here.

What You Notice:

The doubly marked points are 24 and 48, so the LCM of 6 and 8 is 24. The primes give 36 for 12 and 18, and both numbers divide it. For 5 and 7 the answer is 35, which is exactly their product, because they share no prime.

Did you know

There is no greatest common multiple of two numbers, which is why only the lowest one has a name.

The LCM and HCF rules are exact opposites: larger count against smaller, and keeping lone primes against dropping them.

The lowest common bottom number for adding two fractions is the LCM of the two bottoms.

Memory tricks

An LCM keeps everything, at the larger count.

HCF divides into, LCM is divided by.

Practice MCQs with answers (25)

Q1 A number is multiplied by 1, then by 2, then by 3, and the answers are listed in order. A multiple of a number is what you get by multiplying it by beginner
  • A another multiple
  • B a prime number
  • C one of its factors
  • D a whole number
Show answer
Answer: a whole number
Why:

The multiples of 6 start 6, 12, 18.

Q2 One bell rings every 6 minutes and another every 8 minutes, and both have just rung together. They next ring together after beginner
  • A 24 minutes
  • B 14 minutes
  • C 48 minutes
  • D 2 minutes
Show answer
Answer: 24 minutes
Why:

The smallest number both divide.

Q3 The first six multiples of 6 are beginner
  • A 6, 12, 18, 24, 30 and 36
  • B 1, 2, 3, 6, 12 and 18
  • C 6, 8, 12, 18, 24 and 36
  • D 12, 18, 24, 30, 36 and 42
Show answer
Answer: 6, 12, 18, 24, 30 and 36
Why:

Six times each whole number.

Q4 The first five multiples of 8 are beginner
  • A 1, 2, 4, 8 and 16
  • B 8, 12, 16, 24 and 32
  • C 8, 16, 24, 32 and 40
  • D 16, 24, 32, 40 and 48
Show answer
Answer: 8, 16, 24, 32 and 40
Why:

Eight times each whole number.

Q5 The times when both of those bells ring together are listed in order, beginning with the earliest. The first two of them are intermediate
  • A 12 and 24
  • B 24 and 48
  • C 24 and 36
  • D 48 and 72
Show answer
Answer: 24 and 48
Why:

The numbers in both lists.

Q6 A common multiple of 6 and 8 is a time when intermediate
  • A only the first bell rings
  • B only the second bell rings
  • C both bells ring
  • D neither bell rings
Show answer
Answer: both bells ring
Why:

Since both numbers divide it.

Q7 There is no greatest common multiple because the list of them intermediate
  • A has only two entries
  • B stops at the product
  • C never stops at all
  • D stops at the larger number
Show answer
Answer: never stops at all
Why:

After 24 comes 48, then 72.

Q8 Only the lowest common multiple is given a name because advanced
  • A the highest is harder to find
  • B the highest is always the product
  • C the highest is never a whole number
  • D there is no highest one at all
Show answer
Answer: there is no highest one at all
Why:

The list runs on for ever.

Q9 The number 12 is broken down until nothing but primes is left in the list. Broken into primes, 12 is intermediate
  • A one 2 and two 3s
  • B three 2s
  • C two 2s and one 3
  • D one 2 and one 6
Show answer
Answer: two 2s and one 3
Why:

Four times three.

Q10 A common multiple of 12 and 18 must contain enough of every prime to advanced
  • A cover the smaller number
  • B cover the larger number
  • C cover both numbers
  • D avoid both numbers
Show answer
Answer: cover both numbers
Why:

Since both must divide it.

Q11 For the 2s in 12 and 18, the number needed is intermediate
  • A one
  • B two
  • C three
  • D four
Show answer
Answer: two
Why:

Twelve needs two, which also covers the one in 18.

Q12 The 3s are counted in each of 12 and 18 and the larger of the two counts is taken for the LCM. For the 3s the number needed is intermediate
  • A two
  • B one
  • C three
  • D four
Show answer
Answer: two
Why:

Eighteen needs two of them.

Q13 So the LCM of 12 and 18 is intermediate
  • A 6
  • B 18
  • C 216
  • D 36
Show answer
Answer: 36
Why:

Two 2s and two 3s multiplied together.

Q14 An LCM is built from the primes of both numbers, and each prime has to be taken a definite number of times. An LCM takes each prime at the intermediate
  • A smaller count of the two
  • B larger count of the two
  • C total of the two counts
  • D difference of the two counts
Show answer
Answer: larger count of the two
Why:

Which is the opposite of the HCF rule.

Q15 Assertion: The HCF rule and the LCM rule pull in opposite directions. Reason: An HCF must divide both numbers while an LCM must be divisible by both. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, and the reason explains the assertion
Why:

Both are true and the second explains the first. Dividing into both forces the smaller count; being divisible by both forces the larger.

Q16 A prime held by only one of the two numbers is advanced
  • A dropped from the LCM
  • B kept in the LCM
  • C halved in the LCM
  • D doubled in the LCM
Show answer
Answer: kept in the LCM
Why:

Or the answer would not be divisible by that number.

Q17 Compared with an HCF, an LCM keeps advanced
  • A only the part that both of them share
  • B everything, at the larger count
  • C only the primes held by one of them
  • D nothing of either of them at all
Show answer
Answer: everything, at the larger count
Why:

An HCF keeps the shared part at the smaller count.

Q18 Taking 5 and 7, the primes the two share number beginner
  • A none at all
  • B one of them
  • C two of them
  • D five of them
Show answer
Answer: none at all
Why:

Both are prime and different.

Q19 The numbers 5 and 7 share no prime at all, so the LCM has to carry both of them in full. The LCM of 5 and 7 is beginner
  • A 12
  • B 7
  • C 5
  • D 35
Show answer
Answer: 35
Why:

Five times seven.

Q20 Two numbers are coprime, so there is nothing shared to leave out of the LCM at all. For any coprime pair the LCM is intermediate
  • A their total
  • B the larger of them
  • C one
  • D their product
Show answer
Answer: their product
Why:

Since no prime is covered twice over.

Q21 Besides bells and gears, an LCM gives the lowest common intermediate
  • A bottom number for adding fractions
  • B factor of two numbers
  • C difference between two numbers
  • D prime of two numbers
Show answer
Answer: bottom number for adding fractions
Why:

The LCM of the two bottoms.

Q22 Consider these statements about an LCM. I. Both numbers must divide it exactly. II. It can never be larger than the larger of the two numbers. III. It takes every prime at the larger of the two counts. Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I and III only
Why:

I and III are true. The second fails: the LCM of 6 and 8 is 24, which is larger than both.

Q23 Why is 12 not the LCM of 6 and 8? advanced
  • A Six and eight are both even, so their LCM has to be even too
  • B Twelve is smaller than the product of the two numbers given
  • C Twelve is a multiple of six only when the count of 2s is two
  • D Eight does not divide 12, so 12 is not a common multiple at all
Show answer
Answer: Eight does not divide 12, so 12 is not a common multiple at all
Why:

12 holds two 2s and 8 needs three. The first common multiple is 24, where both bells ring together.

Q24 An LCM can never be smaller than advanced
  • A the smaller of the two numbers
  • B the larger of the two numbers
  • C the total of the two
  • D the difference of the two
Show answer
Answer: the larger of the two numbers
Why:

It has to be a multiple of it.

Q25 An LCM can never be larger than advanced
  • A the larger number itself
  • B the total of the two numbers
  • C twice the larger number
  • D the product of the two numbers
Show answer
Answer: the product of the two numbers
Why:

So for 6 and 8 it lies between 8 and 48.

Important short questions (7)

Two bells ring every 6 and every 8 minutes, starting together. Find when they next ring together.

The multiples of 6 are 6, 12, 18, 24 and so on, and those of 8 are 8, 16, 24 and so on. The first number in both lists is 24, so they ring together after 24 minutes.

Why is there no greatest common multiple of two numbers?

The common multiples of 6 and 8 run 24, 48, 72 and onwards without stopping. Since the list never ends, there is no highest one to name.

Break 12 and 18 into primes and find their LCM.

The number 12 is two 2s and one 3, and 18 is one 2 and two 3s. Taking the larger count of each gives two 2s and two 3s, so the LCM is 36.

Why does an LCM take the larger count of each prime while an HCF takes the smaller?

An HCF must divide both numbers, so it can never take more of a prime than a number has. An LCM must be divisible by both, so it must take as many as the greedier one needs.

Why must an LCM keep a prime held by only one of the numbers?

Without that prime the answer would not be divisible by the number holding it. An LCM therefore keeps everything, unlike an HCF.

Find the LCM of 5 and 7, and state the general rule it illustrates.

They share no prime, so the LCM needs one 5 and one 7, giving 35. For any coprime pair, the LCM is simply the product of the two numbers.

Give the two limits on any LCM, using 6 and 8.

An LCM cannot be smaller than the larger number, since it is a multiple of it, and it cannot exceed the product. For 6 and 8 the answer lies between 8 and 48, and 24 sits inside.

Long answer questions (3)

Find the LCM of 6 and 8 by listing multiples, then find the LCM of 12 and 18 by primes, and say why the second method is preferred.

Start by listing. The multiples of 6 are 6, 12, 18, 24, 30 and so on, and those of 8 are 8, 16, 24, 32 and so on. The first number appearing in both lists is 24, so the LCM of 6 and 8 is 24. Now take 12 and 18 by primes. The number 12 is two 2s and one 3, and 18 is one 2 and two 3s. For the 2s, 12 needs two and that also covers the single 2 in 18. For the 3s, 18 needs two. So the LCM is 2 times 2 times 3 times 3, which is 36. The prime method is preferred because listing multiples is slow for larger numbers: the two lists can run on a long way before they meet, while the primes give the answer directly.

Explain why an LCM takes the larger count of each prime and keeps the lone ones, while an HCF does the opposite, using 12 and 18.

The difference comes from what each one has to do. An HCF has to divide both numbers. Take 12, which is two 2s and one 3. An HCF cannot contain more than one 3, because 12 has only one. So it is limited to the smaller count of each shared prime. A prime held by just one number has to be dropped altogether. An LCM has the opposite job: both numbers have to divide IT. Since 12 needs two 2s, the LCM must contain at least two, and since 18 needs two 3s, it must contain at least two of those. So the larger count of each prime is required. For the same reason a lone prime must be kept, since leaving it out would stop the answer being divisible by the number holding it.

Find the LCM of 5 and 7, state the rule for coprime numbers, and give two checks and two limits for any LCM.

The numbers 5 and 7 are both prime and different, so they share no prime factor at all. The LCM must contain one 5 and one 7, which gives 35, and that is simply the two numbers multiplied. The rule it illustrates is that any two coprime numbers have their product as their LCM, because nothing is covered twice over. Two checks apply to every LCM. Both numbers must divide the answer exactly, and nothing smaller must be divisible by both, which is how 12 is ruled out for 6 and 8. Two limits also apply. The answer cannot be smaller than the larger number, since it is a multiple of it, and it cannot exceed the product of the two.

Flashcards (17)

What is a multiple of a number?
What you get by multiplying it by a whole number.
What is a common multiple of two numbers?
A number appearing in both lists of multiples.
Give the LCM of 6 and 8.
Twenty-four.
Why is there no greatest common multiple?
Because the list of common multiples never stops.
Why is listing multiples a poor method for large numbers?
The two lists run on for a long way before they meet.
Break 12 and 18 into prime factors.
Two 2s and one 3, against one 2 and two 3s.
How many of each prime does an LCM take?
The larger count of the two.
Give the LCM of 12 and 18.
Thirty-six.
Why does an LCM take the larger count and an HCF the smaller?
An HCF must divide both, while an LCM must be divisible by both.
Does an LCM keep a prime held by only one number?
Yes, or the answer would not be divisible by that number.
Give the LCM of 5 and 7.
Thirty-five.
What is the LCM of any two coprime numbers?
Their product.
Name two uses of an LCM besides bells.
Gears or timetables, and the common bottom for adding fractions.
What is the first check on an LCM?
Both numbers must divide it exactly.
What is the second check on an LCM?
Nothing smaller must be divisible by both.
What is the lower limit on any LCM?
The larger of the two numbers.
What is the upper limit on any LCM?
The product of the two.

Play this topic

  • Match each pair to its LCM
  • Which rule is it, HCF or LCM?
  • Fact or myth
  • Order these steps for an LCM by primes
  • Match each term to its meaning

HCF times LCM, and a quicker procedure

The HCF multiplied by the LCM equals the two numbers multiplied, because each prime is taken at the smaller count and the larger, which add to the two counts. That gives a shortcut and a check. An HCF can also be found by subtracting the smaller from the larger until the two match.

What you will be able to do

  • State the relation between an HCF, an LCM and the two numbers.
  • Explain the relation from the smaller and larger prime counts.
  • Use the relation as a shortcut and as a check on a pair of answers.
  • Find an HCF by subtracting the smaller from the larger repeatedly.
  • Justify that procedure by showing the common factors never change.

Key points

  • The HCF times the LCM equals the two numbers multiplied.

  • For 20 and 30 that is 10 times 60, which matches 600.

  • The HCF takes the smaller prime count and the LCM the larger.

  • A smaller count plus a larger count is the two counts added.

  • So the shortcut is to find the HCF, then divide the product by it.

  • The relation also checks a pair of answers already found.

  • Subtracting the smaller from the larger, and repeating, gives the HCF.

  • The procedure stops when the two numbers match, not when they reach 1.

  • It works because every step leaves the common factors unchanged.

Full explanation

A pattern worth noticing

Take 20 and 30. Their HCF is 10 and their LCM is 60.

Now multiply those two answers together. Ten times 60 is 600, and 20 times 30 is 600 as well.

Checking it on a second pair

That could be luck, so try another pair. Take 14 and 21, whose HCF is 7 and whose LCM is 42.

Seven times 42 is 294, and 14 times 21 is 294. The same thing has happened again.

The relation

For any two numbers, the HCF multiplied by the LCM equals the two numbers multiplied.

It holds every time, and the reason comes straight from the two rules of the last two topics.

Why it works out

Take any prime, and count how many times it appears in each number. The HCF takes the SMALLER of those two counts and the LCM takes the LARGER.

A smaller count plus a larger count is just the two counts added together.

Every prime is counted the right number of times

So when the HCF and LCM are multiplied, each prime appears as many times as it did in the two numbers altogether.

That is exactly what multiplying the two numbers gives. The relation is not a coincidence at all.

Using it as a shortcut

The relation saves work. Find the easier of the two answers, then get the other by arithmetic.

For 20 and 30, their product is 600. If the HCF of 10 is found first, the LCM is 600 divided by 10, which is 60.

Which one to find first

An HCF is usually the easier one. It is smaller, so a small mistake shows up quickly, and the prime method needs only the shared part.

So find the HCF, then divide the product by it to get the LCM.

A check on a pair of answers

The relation is also a check. If you have found both an HCF and an LCM, their product must match the product of the numbers.

For 14 and 21 we had 7 and 42, and 7 times 42 matched 294. Had it not, one of the two answers would be wrong.

When one number divides the other

Try 7 and 21. Since 7 divides 21, the HCF is 7 and the LCM is 21.

The relation holds: 7 times 21 is 147, and 7 times 21 is the product too. The HCF is the smaller number and the LCM is the larger.

Coprime pairs again

For a coprime pair the HCF is 1, so the relation says the LCM is the product divided by 1.

That is the product itself, which is exactly the rule found in the last topic. The relation explains it.

A quicker procedure for an HCF

There is also a way to find an HCF with no prime factorisation at all. Take 20 and 30, and subtract the smaller from the larger.

That leaves 10, so now consider 20 and 10. Subtract again, leaving 10, so now consider 10 and 10.

Stopping when they match

Once the two numbers match, that number is the HCF. Here both are 10, and the HCF of 20 and 30 is indeed 10.

Try it on 14 and 21. Subtracting gives 7, then 14 and 7 gives 7, so both are 7 and the HCF is 7.

Why subtracting keeps the HCF

The procedure looks like a trick, so it is worth seeing why it works. Suppose some number divides both 20 and 30.

Then it divides their difference of 10 as well, because taking away whole lots of it leaves whole lots of it.

And nothing is gained either

The reverse holds too. Any number dividing both 10 and 20 also divides 30, since 30 is 10 plus 20.

So the two pairs have exactly the same common factors, and therefore the same highest one. Every step preserves the answer.

Which method to use when

Prime factorisation shows the structure and gives the LCM as well. Subtracting is faster when the numbers are awkward to break down.

The relation then supplies the LCM from the HCF, so either route reaches both answers.

What carries forward

The HCF multiplied by the LCM equals the two numbers multiplied, because each prime is taken at the smaller count and the larger, which add to the two counts.

That gives a shortcut, since the easier answer yields the other, and a check on any pair of answers. An HCF can also be found by repeatedly subtracting the smaller from the larger until the two match, which works because every step keeps the common factors unchanged.

Concepts and terms

The relation

For any two numbers, the HCF multiplied by the LCM equals the two numbers multiplied. For 20 and 30 that is 10 times 60 against 600.

Why it holds

For each prime the HCF takes the smaller count and the LCM the larger. A smaller plus a larger is the two counts added, which is what the product contains.

The shortcut

Find the HCF, which is usually easier, then divide the product of the two numbers by it to obtain the LCM in one step.

The subtracting procedure

Take the smaller number from the larger, replace the larger by that difference, and repeat until the two match. That matching number is the HCF.

Why the procedure is safe

A common factor of both numbers divides their difference, and a common factor of the difference and the smaller divides the larger, so nothing is lost.

Watch out

Common misconceptions

The two answers and the shortcut

Scenario:

A pupil finds the HCF of 20 and 30 to be 10 and the LCM to be 60, and notices that 10 times 60 matches 20 times 30. She asks whether that always happens. A classmate says it is a coincidence of round numbers. She then has to find the LCM of 14 and 21, whose HCF she has already worked out as 7. Another classmate reports the HCF of 20 and 30 as 1, having run the subtracting procedure all the way down past 10.

Analysis:

One question has a reason behind it, one claim is wrong, one answer can be had by division, and one procedure was stopped too late.

Activity:

Take five pairs of numbers, find each HCF by subtracting and each LCM by the relation, then check every pair of answers against the product.

Two routes to both answers

Title:

Two routes to both answers

Safety:

Nothing hazardous here.

What You Notice:

Both routes give an HCF of 10 for the first pair and 7 for the second. Dividing the products by those gives 60 and 42, matching the prime method. Every HCF times LCM comes back to the product of its two numbers.

Did you know

The relation explains the coprime rule: an HCF of 1 makes the LCM the product itself.

The subtracting procedure finds an HCF without breaking either number into primes at all.

Every step of that procedure leaves the whole set of common factors unchanged, which is why the answer survives.

Memory tricks

HCF times LCM is the product.

Stop when the two numbers match.

Practice MCQs with answers (25)

Q1 The numbers 20 and 30 are broken into primes and the counts shared by both are taken at the smaller count. Found that way, their HCF is beginner
  • A 5
  • B 2
  • C 60
  • D 10
Show answer
Answer: 10
Why:

The largest number dividing both.

Q2 The same two numbers are taken again, this time with every prime at the larger of its two counts. Found that way, their LCM is beginner
  • A 600
  • B 30
  • C 60
  • D 10
Show answer
Answer: 60
Why:

The smallest number both divide.

Q3 Multiplying those two answers together gives intermediate
  • A 70
  • B 70 exactly
  • C 600
  • D 6
Show answer
Answer: 600
Why:

Ten times sixty.

Q4 The two numbers 20 and 30 are multiplied together, before any HCF or LCM is brought into it at all. Multiplied together they give beginner
  • A 60
  • B 600
  • C 50
  • D 10
Show answer
Answer: 600
Why:

The same as the HCF times the LCM.

Q5 The numbers 14 and 21 share a single prime, and the HCF and LCM of the pair have both to be found. For 14 and 21 they are intermediate
  • A 7 and 42
  • B 7 and 21
  • C 1 and 294
  • D 14 and 42
Show answer
Answer: 7 and 42
Why:

Seven divides both, and 42 is divisible by both.

Q6 Multiplying 7 by 42 gives intermediate
  • A 49
  • B 294
  • C 147
  • D 588
Show answer
Answer: 294
Why:

Which is also 14 times 21.

Q7 Any two numbers are taken and their HCF and LCM are multiplied together, whatever the numbers happen to be. That product equals intermediate
  • A the two numbers multiplied
  • B the two numbers added
  • C the larger number
  • D the smaller number
Show answer
Answer: the two numbers multiplied
Why:

It holds every time.

Q8 For any prime, the count taken by the HCF is the intermediate
  • A smaller of the two
  • B larger of the two
  • C total of the two
  • D difference of the two
Show answer
Answer: smaller of the two
Why:

And the LCM takes the larger.

Q9 A smaller count added to a larger count gives advanced
  • A the two counts added
  • B twice the smaller count
  • C twice the larger count
  • D the difference of the counts
Show answer
Answer: the two counts added
Why:

Which is why the relation holds.

Q10 So in the HCF times the LCM, each prime appears as often as advanced
  • A the smaller of the two numbers held it
  • B the larger of the two numbers held it
  • C whichever number happened to hold it
  • D the two numbers held it altogether
Show answer
Answer: the two numbers held it altogether
Why:

Exactly as in the product.

Q11 Consider these statements about the HCF and LCM relation. I. The HCF times the LCM equals the two numbers multiplied. II. For 20 and 30 that is 10 times 60, which matches 600. III. The relation holds for every pair, coprime or not Which statements are correct? advanced
  • A I and II only
  • B II and III only
  • C I and III only
  • D I, II and III
Show answer
Answer: I, II and III
Why:

All three are true. 20 and 30 are not coprime and the relation still holds exactly.

Q12 Knowing the HCF of 20 and 30 to be 10, the LCM can be found by intermediate
  • A multiplying 600 by 10
  • B dividing 600 by 10
  • C dividing 10 by 600
  • D adding 10 to 600
Show answer
Answer: dividing 600 by 10
Why:

The product divided by the HCF.

Q13 Of the two quantities, one can be checked against both numbers in a moment and the other cannot. The easier one to find is intermediate
  • A the HCF
  • B the LCM
  • C whichever is larger
  • D whichever is even
Show answer
Answer: the HCF
Why:

It is smaller, and needs only the shared part.

Q14 Why is an HCF usually the easier of the two to find? advanced
  • A It is smaller, so a mistake in it shows up quickly on checking
  • B It uses the larger count of each prime in the breakdown given
  • C An LCM cannot be found at all without first finding the HCF
  • D Only even numbers have an HCF worth looking for in practice
Show answer
Answer: It is smaller, so a mistake in it shows up quickly on checking
Why:

The HCF is at most the smaller number, so it can be tested against both in a moment. The LCM may be as large as the product.

Q15 Having found both an HCF and an LCM, you can check them by intermediate
  • A adding them together
  • B dividing one by the other
  • C multiplying them together
  • D comparing their sizes
Show answer
Answer: multiplying them together
Why:

Their product must match the numbers multiplied.

Q16 For 7 and 21, the HCF and LCM are intermediate
  • A 7 and 147
  • B 7 and 21
  • C 1 and 147
  • D 21 and 7
Show answer
Answer: 7 and 21
Why:

Since 7 divides 21 exactly.

Q17 Two numbers are taken in which the smaller divides the larger exactly, as 7 divides 21. For such a pair the HCF and LCM are advanced
  • A the larger and the smaller
  • B one and the product
  • C the product and one
  • D the smaller and the larger
Show answer
Answer: the smaller and the larger
Why:

As with 7 and 21.

Q18 For a coprime pair, the relation gives an LCM of intermediate
  • A half the product
  • B the larger number
  • C one
  • D the product itself
Show answer
Answer: the product itself
Why:

Since the HCF is 1 and the product is divided by it.

Q19 The subtracting procedure is started on 20 and 30 by taking the smaller away from the larger. After the first step it leaves intermediate
  • A 30 and 10
  • B 20 and 10
  • C 20 and 30
  • D 10 and 10
Show answer
Answer: 20 and 10
Why:

Thirty less 20 is 10.

Q20 The subtracting procedure is repeated again and again, and at some point it has to be stopped. It stops when the two numbers intermediate
  • A reach one
  • B reach zero
  • C differ by one
  • D match each other
Show answer
Answer: match each other
Why:

And that number is the HCF.

Q21 Run on 14 and 21, the procedure ends at intermediate
  • A 1 and 1
  • B 14 and 7
  • C 7 and 7
  • D 21 and 14
Show answer
Answer: 7 and 7
Why:

Twenty-one less 14 is 7, then 14 less 7 is 7.

Q22 A number divides both 20 and 30, so it must also divide what is left when one is taken from the other. It must also divide advanced
  • A their total of 50
  • B their product of 600
  • C their difference of 10
  • D the number 1 only
Show answer
Answer: their difference of 10
Why:

Whole lots taken from whole lots leave whole lots.

Q23 Anything dividing both 10 and 20 must also divide advanced
  • A their total of 30
  • B their difference of 10
  • C their product of 200
  • D the number 1 only
Show answer
Answer: their total of 30
Why:

Which is why nothing is lost either way.

Q24 Assertion: Every step of the subtracting procedure leaves the common factors unchanged. Reason: The procedure stops when the two numbers match each other. advanced
  • A Both true, and the reason explains the assertion
  • B Both true, but the reason does not explain it
  • C The assertion is true and the reason is false
  • D The assertion is false and the reason is true
Show answer
Answer: Both true, but the reason does not explain it
Why:

Both statements are true, but the reason does not explain the assertion. The factors survive because anything dividing both numbers also divides their difference.

Q25 Two large numbers are given whose prime breakdowns are slow and awkward to work out by hand. The subtracting method is better when the numbers are intermediate
  • A both of them even numbers
  • B both of them odd numbers
  • C awkward to break down
  • D both of them prime numbers
Show answer
Answer: awkward to break down
Why:

Primes show the structure and give the LCM too.

Important short questions (7)

Give the HCF and LCM of 20 and 30, and show the relation between them.

The HCF is 10 and the LCM is 60. Their product is 600, which is also 20 times 30.

State the relation between the HCF and LCM of two numbers, and check it on 14 and 21.

The HCF multiplied by the LCM equals the two numbers multiplied. For 14 and 21 the HCF is 7 and the LCM is 42, and 7 times 42 is 294, which is 14 times 21.

Why does that relation hold for every pair of numbers?

For each prime the HCF takes the smaller count and the LCM takes the larger. A smaller plus a larger is the two counts added, so each prime appears exactly as often as in the product.

The HCF of 20 and 30 is 10. Use the relation to find their LCM.

The product of the numbers is 600. Dividing by the HCF gives 600 divided by 10, which is 60.

Which of an HCF and an LCM is usually worth finding first, and why?

The HCF, because it is smaller so a mistake shows up quickly, and the prime method needs only the shared part. The LCM then follows by division.

Use the subtracting procedure on 14 and 21.

Twenty-one less 14 leaves 7, so take 14 and 7. Fourteen less 7 leaves 7, so both numbers are now 7, and the HCF is 7.

Why does subtracting the smaller number from the larger keep the HCF unchanged?

Anything dividing both numbers divides their difference too, and anything dividing the difference and the smaller divides the larger. So the common factors are exactly the same before and after.

Long answer questions (3)

Explain why the HCF of two numbers multiplied by their LCM equals the two numbers multiplied, checking it on 20 and 30.

Take any prime and count how many times it appears in each of the two numbers. The HCF rule takes the smaller of those two counts, and the LCM rule takes the larger. Now notice an arithmetic fact about any two numbers: the smaller of them added to the larger is simply the two of them added. So when the HCF and LCM are multiplied together, every prime appears as many times as the two original numbers held it altogether. That is exactly what multiplying the two numbers produces, so the two results must agree. Checking on 20 and 30, the HCF is 10 and the LCM is 60, giving 600. The product 20 times 30 is 600 as well. The relation is therefore no coincidence, but a consequence of the two counting rules.

Describe the subtracting procedure for an HCF, run it on 20 and 30, and explain why it cannot change the answer.

The procedure is to take the smaller number from the larger, replace the larger by that difference, and repeat until the two numbers match. Run it on 20 and 30. Thirty less 20 leaves 10, so we now have 20 and 10. Twenty less 10 leaves 10, so we now have 10 and 10. The two match, so the HCF is 10, which agrees with the prime method. Now why it cannot change the answer. Suppose some number divides both 20 and 30. Then it divides their difference of 10 as well, because whole lots of it taken from whole lots of it leave whole lots of it. The reverse also holds: anything dividing 10 and 20 divides 30, which is their total. So the two pairs have exactly the same common factors, and the highest of them is therefore preserved at every step.

Explain two uses of the HCF and LCM relation, and what it says about a coprime pair and about a pair where one number divides the other.

The first use is as a shortcut. Find whichever answer is easier, usually the HCF, then divide the product of the numbers by it to get the other. For 20 and 30 the product is 600, so once the HCF of 10 is known the LCM comes out as 60 with one division. The second use is as a check. If both answers have been found separately, their product must equal the product of the two numbers, and for 14 and 21 that was 7 times 42 against 294. A mismatch would mean one answer is wrong. For a coprime pair the HCF is 1, so the relation makes the LCM the product itself, which explains the rule met earlier. Where one number divides the other, as with 7 and 21, the HCF is the smaller number and the LCM is the larger.

Flashcards (17)

Give the HCF and LCM of 20 and 30.
Ten and sixty.
What is 20 times 30?
Six hundred.
Give the HCF and LCM of 14 and 21.
Seven and forty-two.
State the relation between an HCF and an LCM.
The HCF times the LCM equals the two numbers multiplied.
For any prime, what count does the HCF take?
The smaller of the two counts.
Why does the relation hold?
A smaller count plus a larger count is the two counts added.
How can the relation be used as a shortcut?
Find the easier answer, then divide the product by it.
Which of an HCF and an LCM is usually easier to find?
The HCF.
How does the relation check a pair of answers?
Their product must equal the product of the two numbers.
Give the HCF and LCM of 7 and 21.
Seven and twenty-one.
What are the HCF and LCM when one number divides the other?
The smaller number and the larger number.
Why is the LCM of a coprime pair their product?
Because the HCF is 1, so the product divided by 1 is the product.
Describe the subtracting procedure for an HCF.
Take the smaller from the larger and repeat until the two match.
Run the procedure on 20 and 30.
Thirty less 20 is 10, then 20 less 10 is 10, so the HCF is 10.
Run the procedure on 14 and 21.
Twenty-one less 14 is 7, then 14 less 7 is 7, so the HCF is 7.
Why does a common factor of two numbers divide their difference?
Taking whole lots of it from whole lots of it leaves whole lots.
When is the subtracting method better than prime factorisation?
When the numbers are awkward to break into primes.

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Class 7 Mathematics Chapter 11 — frequently asked questions

List the common factors of 24 and 36 and give their HCF.

The common factors are 1, 2, 3, 4, 6 and 12. The highest of them is 12, so the HCF is 12.

Why is listing every factor a poor method for large numbers?

It is slow, and it is easy to miss a factor. A single omission gives the wrong answer, so prime factorisation is used instead.

Break 18 and 45 into prime factors.

The number 18 is 2 times 9, and 9 is 3 times 3. So it is one 2 and two 3s. The number 45 is 3 times 15, and 15 is 3 times 5. So it is two 3s and one 5.

Two bells ring every 6 and every 8 minutes, starting together. Find when they next ring together.

The multiples of 6 are 6, 12, 18, 24 and so on, and those of 8 are 8, 16, 24 and so on. The first number in both lists is 24, so they ring together after 24 minutes.

Why is there no greatest common multiple of two numbers?

The common multiples of 6 and 8 run 24, 48, 72 and onwards without stopping. Since the list never ends, there is no highest one to name.

Break 12 and 18 into primes and find their LCM.

The number 12 is two 2s and one 3, and 18 is one 2 and two 3s. Taking the larger count of each gives two 2s and two 3s, so the LCM is 36.

Give the HCF and LCM of 20 and 30, and show the relation between them.

The HCF is 10 and the LCM is 60. Their product is 600, which is also 20 times 30.

State the relation between the HCF and LCM of two numbers, and check it on 14 and 21.

The HCF multiplied by the LCM equals the two numbers multiplied. For 14 and 21 the HCF is 7 and the LCM is 42, and 7 times 42 is 294, which is 14 times 21.

Why does that relation hold for every pair of numbers?

For each prime the HCF takes the smaller count and the LCM takes the larger. A smaller plus a larger is the two counts added, so each prime appears exactly as often as in the product.

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